Answer:
<em>C:</em><em> </em><em>is</em><em> </em><em>co</em><em>rrect</em><em> answer</em>
<em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em><em>-</em>
<em>
</em>
97.2% on the final.
Find the total amount of points needed to get a 93%. 150+150+150+250 = 700 total points. 700*.93 = 651 total points needed to get 93%. find the points received from the other quizzes and subtract the sum from 651 to find how many points need to be scored on the final.
150*.88=132 (test 1)
150*.94=141 (test 2)
150*.90=135 (test 3)
132+141+135= 408
651-408 = 243 points to score on the final exam.
243/250 =.972 or 97.2%
Answer:
x = 1 
Step-by-step explanation:
Expressing the diagram as an equation , that is
6x - 3 = 4
=
( multiply through by 2 to clear the fraction )
12x - 6 = 9 ( add 6 to both sides )
12x = 15 ( divide both sides by 12 )
x =
=
= 1 
Answer:
77.5
Step-by-step explanation:
in this excercise the average is 4 months (January, Febuary, March, April)
the average rate is:

Answer:
n = 100 scores from a population with σ = 20
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a random variable X, with mean
and standard deviation
, the sample means with size n can be approximated to a normal distribution with mean
and standard deviation, which is also called standard error, of 
n = 5 scores from a population with σ = 20

n = 5 scores from a population with σ = 80

n = 100 scores from a population with σ = 20
.
This one is the correct answer.
n = 100 scores from a population with σ = 40
.