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3 years ago

Which inequality is equivalent to this one? Help with this question

Mathematics

2 answers:

Ira Lisetskai [31]3 years ago

8 0

Answer:

A. the first one

Step-by-step explanation:

andreyandreev [35.5K]3 years ago

4 0

Answer:

The last one

Step-by-step explanation:

$y - 8 \leqslant - 2 \\ y \leqslant 8 - 2 \\ y \leqslant 6\\ \\ \\ y - 8 + 2 \leqslant - 2 + 2 \\ y - 6 \leqslant 0 \\ y \leqslant 6$

$hope \: i \: answered \: your \: question. \\ good \: luck$

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When will the equation xn = c, where c is a whole number, have two solutions? Explain.

Kazeer [188]

If x=n then it would have 2 solutions because it would be x^2 = c which has a positive and negative solution but idk if that is what you are asking for

3 0

3 years ago

The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airp

motikmotik

Answer:

The 95% confidence interval for the population mean rating is (5.73, 6.95).

Step-by-step explanation:

We start by calculating the mean and standard deviation of the sample:

$M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{50}(6+4+6+. . .+6)\\\\\\M=\dfrac{317}{50}\\\\\\M=6.34\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{49}((6-6.34)^2+(4-6.34)^2+(6-6.34)^2+. . . +(6-6.34)^2)}\\\\\\s=\sqrt{\dfrac{229.22}{49}}\\\\\\s=\sqrt{4.68}=2.16\\\\\\$

We have to calculate a 95% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=6.34.

The sample size is N=50.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

$s_M=\dfrac{s}{\sqrt{N}}=\dfrac{2.16}{\sqrt{50}}=\dfrac{2.16}{7.071}=0.305$

The degrees of freedom for this sample size are:

$df=n-1=50-1=49$

The t-value for a 95% confidence interval and 49 degrees of freedom is t=2.01.

The margin of error (MOE) can be calculated as:

$MOE=t\cdot s_M=2.01 \cdot 0.305=0.61$

Then, the lower and upper bounds of the confidence interval are:

$LL=M-t \cdot s_M = 6.34-0.61=5.73\\\\UL=M+t \cdot s_M = 6.34+0.61=6.95$

The 95% confidence interval for the mean is (5.73, 6.95).

4 0

4 years ago

Identify a way in which an individual develops a credible persona, both in person and online.

Y_Kistochka [10]

Answer:

Being reliable

Step-by-step explanation:

Being reliable

Honest

and kind

3 0

3 years ago

Dominic is buying supplies for his poetry class. He likes to write his poems in black ink, then decorate the pages with colorful

pychu [463]

Answer:

No, they do not.

Step-by-step explanation:

Mega Writer pack: 6color:9black ratio or 9 black pens out of 15 total pens.

Mini Writer pack 3color:6black ratio or 6 black pens out of 9.

6:9 is not equal to 3:6 and 9/15 is not equal to 6/9.

6 0

3 years ago

This set of ordered pairs shows a relationship between x and y. {(0, -2), (3, 7), (6, 16), (6, 15), (8, 21), (10, 28), (11,31)}

Hunter-Best [27]

Answer:

The closest to the output when the input is approximately 12

Step-by-step explanation:

The given (x, y) coordinates are;

The line of best fit is

x, 0, 3, 6, 6, 8, 10, 11

y, -2, 7, 16, 15, 21, 28, 31

The line of best fit can be obtained from the scatter plot of the given data from where a linear pattern is apparent

A linear line of best fit is a trend line that gives an overall cumulative minimum distance of all the points from the line

The method for constructing a line of best fit includes;

1) The least Squares Method

2) The method of linear regression

3) Construction of line of best fit

a) The area method

b) The dividing method

The least squares equation is given as follows;

$\hat y$ = a + b·x

$b = \dfrac{\Sigma (x_i - \overline x) \cdot (y_i - \overline y)}{\Sigma (x_i - \overline x)^2 }$

From MS Excel, we have;

${\Sigma (x_i - \overline x) \cdot (y_i - \overline y)}{ }$ = 266.8571

${\Sigma (x_i - \overline x)^2 }$ = 89.42857

∴ b = 266.8571/89.42857 ≈ 2.984

$a =\overline y- b \cdot \overline x$

From MS Excel, with the given data, we get;

$\overline y$ = 16.57143

$\overline x$ = 6.285714

Therefore;

a = 16.57143 - 2.984 × 6.285714 = -2.185

Therefore, we get the following regression equation;

$\hat y$ = -2.185 + 2.9·x

Where;

x = The input

$\hat y$ = The output

Therefore, when x = 5, we get;

$\hat y$ = -2.185 + 2.9 × 5 = 12.315

Therefore, the closest to the output when the input is 5, y ≈ 12

8 0

3 years ago