Answer:
6, 2, 2/3, 2/9, 2/27, 2/81
Step-by-step explanation:
The nth term of a geometric progression is expressed as;
Tn = ar^n-1
a is the first term
n is the number of terms
r is the common ratio
Given
a = 6
r = 1/3
when n = 1
T1 = 6(1/3)^1-1
T1 = 6(1/3)^0
T1 = 6
when n = 2
T2= 6(1/3)^2-1
T2= 6(1/3)^1
T2 = 2
when n = 3
T3 = 6(1/3)^3-1
T3= 6(1/3)^2
T3= 6 * 1/9
T3 = 2/3
when n = 4
T4 = 6(1/3)^4-1
T4= 6(1/3)^3
T4= 6 * 1/27
T4 = 2/9
when n = 5
T5 = 6(1/3)^5-1
T5= 6(1/3)^4
T5= 6 * 1/81
T5 = 2/27
when n = 6
T6 = 6(1/3)^6-1
T6= 6(1/3)^5
T6= 6 * 1/243
T6 = 2/81
Hence the first six terms are 6, 2, 2/3, 2/9, 2/27, 2/81
Answer: The widths of Kyle and Myla's boxes is the same as 2 ft.
Step-by-step explanation:
Formula : Volume of cuboidal box = length x width x height

Given: Kyle has a storage box that is 2 ft. Long, 3 ft. High, and has a volume of 12 ft³ .

Myla has a storage box that is 4 ft. High, 2 ft. Long, and has a volume of 16 ft³.

Hence, the widths of Kyle and Myla's boxes is the same as 2 ft.
Answer: the balance in his check register will be $76 over the balance on his bank account
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Answer:
5.78% probability that exactly 2 of them use their smartphones in meetings or classes.
Step-by-step explanation:
For each adult, there are only two possible outcomes. Either they use their smarthphone in meetings or classes, or they do not. The probability of an adult using their smartphone on meetings or classes is independent of other adults. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
63% use them in meetings or classes.
This means that 
7 adult smartphone users are randomly selected
This means that 
Find the probability that exactly 2 of them use their smartphones in meetings or classes.
This is P(X = 2).


5.78% probability that exactly 2 of them use their smartphones in meetings or classes.