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3 years ago

How many ways can you arrange 10 numbers

Mathematics

1 answer:

kkurt [141]3 years ago

8 0

Answer:

3628800

Step-by-step explanation:

There are 10 options for the first number.

That leaves 9 options for the second number.

That leaves 8 options for the third number.

So on and so forth.

The number of ways 10 numbers can be arranged is:

10×9×8×7×6×5×4×3×2×1

= 10!

= 3628800

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3 years ago

Read 2 more answers

-49 + (-46) = -50 + 27 =

vesna_86 [32]

1. -96 just simply add those two and it will be -96

2. -50 +27= change the signs- -50- -27= -23 just subtract

Hope this helps!

3 0

3 years ago

Ramona deposits $2,500 into a savings account that pays 4.5% interest compounded annually. If Ramona makes no deposits or withdr

kicyunya [14]

Answer: She will earn $352.92 as interest.

Step-by-step explanation:

Formula for compound interest $= P((1+r)^t-1)$

, where P= principal value, r = rate of interest(in decimal) , t= time

As per given , we have

P = $2,500

r = 4.5% = 0.045

t= 3 years

then, Compound interest = $2500((1+0.045)^3-1)=2500((1.045)^3-1)$

$=2500(1.141166125-1)=2500(0.141166125)\\\\\approx\ \$352.92$

Hence, she will earn $352.92 as interest.

5 0

3 years ago

A trader bought x mangoes at the rate of 4 mangoes for 10 naira five of the mangoes were bad so he sold the remaining at the rat

Ilya [14]

Answer:

20 mangoes.

Step-by-step explanation:

Given:

Total number of mangoes, a trader bought = $x$

A trader bought at the rate of 4 mangoes for 10 naira.

Five of the mangoes were bad.

He sold the remaining at the rate of 5 mangoes for 20 naira.

He made a gain of 10 naira

Question asked:

Total number of mangoes, a trader bought = $x$ = ?

Solution:

Unitary method

Cost price of 4 mangoes = 10 naira.

Cost price of 1 mango = $\frac{10}{4}$

Cost price of $x$ mango = $\frac{10}{4}\times x= \frac{5}{2} x$

As 5 of the mangoes were bad and he sold the remaining mangoes, then Total number of mangoes sold = $x-5$

Sale price of 5 mangoes = 20 naira

Sale price of 1 mango = $\frac{20}{5}$

Sale price $x-5$ of mango = $\frac{20}{5}\times(x-5)=4(x-5)=4x-20$

Now, as we know,

$Gain = Sale price - cost price$

$10 = 4x-20 -\frac{5}{2} x\\ 10=4x-\frac{5}{2} x-20\\10=\frac{8x-5x}{2} -20$

$10 =\frac{3x}{2} -20$

Adding both sides by 20

$30=\frac{3x}{2}$

Multiplying both sides by 2

$60 = 3x$

Dividing both sides by 3

$x=20$

Therefore, total number of mangoes, a trader bought is 20.

3 0

3 years ago