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mote1985 [20]
3 years ago
8

Need help ASAP with this stuff

Mathematics
1 answer:
Mandarinka [93]3 years ago
7 0
= xy√y +2xy^2√x+ xy<span>√y
= </span> 2xy√y + 2xy^2√x 

answer is B. second choice
2xy√y + 2xy^2√x 
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If f(x) = 5x, what is rl (x)?<br><br><br> NEED HELP !!
velikii [3]

Answer:

the second one is your answer

7 0
3 years ago
Dont mind the answer that I picked on accident and pls dont send no PDF or a image to download
Leto [7]

Answer:

I guess that X measures 50° because X and 50 are vertically opposite angles...

7 0
2 years ago
Simplify square root of 72
LuckyWell [14K]
(square root of  72)  =  square root of (36  times  2)

That's the same as  (square root of  36)  times  (square root of  2).

But the square root of  36  is  6 .

So the square root of  72  is    (6)  times  (square root of  2) .
4 0
3 years ago
Read 2 more answers
An agency has started charging a user fee to park at selected trailheads and​ cross-country ski lots. Some users object to this​
Nesterboy [21]

Answer:

Users who park at the selected trailheads and​ cross-country ski lots. ; Convenience sampling

Step-by-step explanation:

A) The population of interest:

The population of interest should include the concerned individuals which would be those who park at the selected trailheads and cross-country ski lots.

B) By sampling the first 50 users encountered at each fee areas shows that the researcher prioritizes ease or convenience while choosing samples from a population. The first 50 fee users represents the most easily accessible users. Hence, the reason the adopted sampling method is called convenience sampling.

3 0
3 years ago
What are the solutions to the equation x2−12x+100=0?
marysya [2.9K]

Answer:

x=6+8i

x=6-8i

Step-by-step explanation:

x^2-12x+100=0

solve by quadratic formula.

\frac{-b+-\sqrt{b^2-4(a*c)} }{2*a}

\frac{12+\sqrt{(-12)^2-4*(1*100)} }{2*1}

\frac{12-\sqrt{(-12)^2-4*(1*100)} }{2*1}

which is

x=\frac{12+16i}{2}

x=\frac{12-16i}{2}

Simplify.

x=6+8i

x=6-8i

Solved.


Hope this helps.

8 0
2 years ago
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