Let the required equation be y = mx + c; where y = 1, m = f'(0), x = 0
f(a) = sec(a)
f'(a) = sec(a)tan(a)
f'(0) = sec(0)tan(0) = 0
y = mx + c
1 = 0(0) + c
c = 1
Therefore, required equation is
y = 1.
9514 1404 393
Answer:
1. (256/3)π ft³
2. 33.49 ft³
Step-by-step explanation:
1. Put 4 ft into the formula where r is, then simplify.
V = (4/3)π(4 ft)³ = (256/3)π ft³
__
2. The radius is half the diameter, so is 2 ft. Put that in the formula, along with the value for π, and do the arithmetic.
V = (4/3)(3.14)(2 ft)³ ≈ 33.49 ft³
The answer is 345 because you are suppose to multiply then add them togther
Haha, part of my final today was about this! Don't worry, I got you!
y=2/3x-4
(the 2/3 is supposed to be a fraction)
