find the least common denominator of the following rational expression 1/x-5 , x+3/x^2-10x+25, 7x/x^2-25

1 answer:

5 0

Hello there!
Find the last common denominator of the following rational expression 1/x-5 , x+3/x^2-10x+25, 7x/x^2-25

Find the LCD.
$x^{2} (x-5)(x+5)$

Answer: $x^{2} (x-5)(x+5)$

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What is 1200 x 1200? (this is just becouse i was bored) Plz answer me thx

lawyer [7]

Answer:

$\tt{}1.440.000 \\$

Step-by-step explanation:

$\tt{}1.200 \times 1.200 \: \: \: \: \: \: \: \: \: \: \\ \\ \tt{}((12 \times 12) + (0000)) \\ \\ 1.440.000 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \\$

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2 years ago

Tell whether the ordered pair is a solution of the given system. (-2,-4) {y=1/2x -3, y=-2x-8}

kompoz [17]

Answer:

The ordered pair $(-2,\, -4)$ is indeed a solution to the system:

$\left\lbrace\begin{aligned} & y = \frac{1}{2}\, x - 3 \\ & y = -2\, x - 8\end{aligned}\right.$ .

Step-by-step explanation:

Consider a system of equations about variables $x$ and $y$ . An ordered pair $(x_{0},\, y_{0})$ (where $x_{0}$ and $y_{0}$ are constant) is a solution to that system if and only if all equations in that system hold after substituting in $x = x_{0}$ and $y = y_{0}$ .

For the system in this question, $(-2,\, -4)$ would be a solution only if both equations in the system hold after replacing all $x$ in equations of the system with $(-2)$ and all $y$ with $(-4)$ .

The $\texttt{LHS}$ of the equation $y = (1/2)\, x - 3$ would become $(-4)$ . The $\texttt{RHS}$ of that equation would become $(1/2) \, (-2) - 3$ . The two sides are indeed equal.

Similarly, the $\texttt{LHS}$ of the equation $y = -2\, x - 8$ would become $(-4)$ . The $\texttt{RHS}$ of that equation would become $(-2)\, (-2) - 8$ . The two sides are indeed equal.

Thus, $x = (-2)$ and $y = (-4)$ simultaneously satisfy both equations of the given system. Therefore, the ordered pair $(-2,\, -4)$ would indeed be a solution to that system.