100
if x=10 10 times 5 equals 50 times 2 is 100
Answer:
There are 165 ways to distribute the blackboards between the schools. If at least 1 blackboard goes to each school, then we only have 35 ways.
Step-by-step explanation:
Essentially, this is a problem of balls and sticks. The 8 identical blackboards can be represented as 8 balls, and you assign them to each school by using 3 sticks. Basically each school receives an amount of blackboards equivalent to the amount of balls between 2 sticks: The first school gets all the balls before the first stick, the second school gets all the balls between stick 1 and stick 2, the third school gets the balls between sticks 2 and 3 and the last school gets all remaining balls.
The problem reduces to take 11 consecutive spots which we will use to localize the balls and the sticks and select 3 places to put the sticks. The amount of ways to do this is
As a result, we have 165 ways to distribute the blackboards.
If each school needs at least 1 blackboard you can give 1 blackbooard to each of them first and distribute the remaining 4 the same way we did before. This time there will be 4 balls and 3 sticks, so we have to put 3 sticks in 7 spaces (if a school takes what it is between 2 sticks that doesnt have balls between, then that school only gets the first blackboard we assigned to it previously). The amount of ways to localize the sticks is
. Thus, there are only 35 ways to distribute the blackboards in this case.
Let's assume
length of rectangle =L
width of rectangle =W
You enclose 3 sides of the garden with 40 feet of fencing
so, we get

now, we can solve for L

we know that
area of rectangle is


now, we can plug

now, we can solve for W

we can use quadratic formula


we can take anyone value ..because both are giving positive value
first dimensions:

now, we can find L


so, length is 34.142feet
width is 2.929 feet
Second dimensions:

now, we can find L


so, length is 5.858feet
width is 17.071 feet
Answer:
y=-3x+2
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(-1-5)/(1-(-1))
m=-6/(1+1)
m=-6/2
m=-3
y-y1=m(x-x1)
y-5=-3(x-(-1))
y-5=-3(x+1)
y=-3(x+1)+5
y=-3x-3+5
y=-3x+2
Answer:
508,901
Step-by-step explanation: