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Over [174]
3 years ago
6

box contains 15 items,4 of which are defective and 11 are good. Two items are selected. What is probability that the first is go

od and the second defective?
Mathematics
2 answers:
jeka943 years ago
7 0
We have an 11 out of 15 chance, that we can pick a good item, and a 4 out of 15 chance at picking a defect.

By multiplying the two probabilities together, we want to simultaneously pick out two items with order.

Thus, the probability is: 11/15 · 4/15 = 44/225
Taya2010 [7]3 years ago
4 0
Defective 1out of 4
effective 1out of 11
i think 
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Use the Divergence Theorem to evaluate the following integral S F · N dS and find the outward flux of F through the surface of t
Xelga [282]

Answer:

Result;

\int\limits\int\limits_S { \textbf{F}} \, \cdot \textbf{N} d {S} = 32\pi

Step-by-step explanation:

Where:

F(x, y, z) = 2(x·i +y·j +z·k) and

S: z = 0, z = 4 -x² - y²

For the solid region between the paraboloid

z = 4 - x² - y²

div F        

For S: z = 0, z = 4 -x² - y²

We have the equation of a parabola

To verify the result for F(x, y, z) = 2(x·i +y·j +z·k)

We have for the surface S₁ the outward normal is N₁ = -k and the outward normal for surface S₂ is N₂ given by

N_2 = \frac{2x \textbf{i} +2y \textbf{j} + \textbf{k}}{\sqrt{4x^2+4y^2+1} }

Solving we have;

\int\limits\int\limits_S { \textbf{F}} \, \cdot \textbf{N} d {S} = \int\limits\int\limits_{S1} { \textbf{F}} \, \cdot \textbf{N}_1 d {S} + \int\limits\int\limits_{S2} { \textbf{F}} \, \cdot \textbf{N}_2 d {S}

Plugging the values for N₁ and N₂, we have

= \int\limits\int\limits_{S1} { \textbf{F}} \, \cdot \textbf{(-k)}d {S} + \int\limits\int\limits_{S2} { \textbf{F}} \, \cdot  \frac{2x \textbf{i} +2y \textbf{j} + \textbf{k}}{\sqrt{4x^2+4y^2+1} } d {S}

Where:

F(x, y, z) = 2(xi +yj +zk) we have

= -\int\limits\int\limits_{S1} 2z \ dA + \int\limits\int\limits_{S2} 4x^2+4y^2+2z \ dA

= -\int\limits^2_{-2} \int\limits^{\sqrt{4-y^2}} _{-\sqrt{4-y^2}} 2z \ dA + \int\limits^2_{-2} \int\limits^{\sqrt{4-y^2}} _{-\sqrt{4-y^2}} 4x^2+4y^2+2z \ dA

= \int\limits^2_{-2} \int\limits^{\sqrt{4-y^2}} _{-\sqrt{4-y^2}} 4x^2+4y^2 \ dxdy

= \int\limits^2_{-2} \frac{(16y^2 +32)\sqrt{-(y^2-4)} }{3} dy

= 32π.

6 0
4 years ago
Solve for x
victus00 [196]
The lesser x is 2 and the greater x is 3. The x values can be determined by setting each set of numbers in parenthesis equal to 0, so 3x-6=0 and -x+3=0. To solve, take the first set, 3x-6=0 and divide by the greatest common factor, 3, leaving you with x-2=0. Add 2 to each side so that x=2. On the other side, take -x+3=0 and subtract three from each side. Take your new equation -x=-3 and multiply by -1 so that x=3. Therefore x=3 and x=2.
5 0
3 years ago
The cost of renting a jet ski over a certain number of hours can be represented by the equation y=40x + 50. How much would it co
lesya [120]

Answer:

$170

Step-by-step explanation:

Let's say that x represents the amount of hours, so therefore, x will be replaced by 3:

y = (40 * 3) + 50

So, solve inside the parentheses:

y = (40 * 3) + 50

y = 120 + 50

Solve:

y = 120 + 50

y = 170

So, a jet ski would cost $170 to rent for 3 hours

Hope this helps :)

3 0
3 years ago
2/3(p-12)=-(2p-1)+7<br> A. all real numbers<br> B. −6<br><br> C. –4<br> D. 4
Andrei [34K]

Answer:

p=6

Was option B supposed to be 6 instead of -6?

Work:

2/3p-8=-2p+8

2p-24=-6p+24

8p=48

p=6

3 0
3 years ago
The sum of two numbers is 100, The difference between the two numbers is 95
luda_lava [24]

Answer:

Let the numbers be x and y

x+y=100

x-y=95

taking x-y=95

x=95+y

x+y=100

95 + y +y = 100

2y=100-95

y=5/2

y=2.5

x=95+y

x=95+2.5

x= 97.5

Hope it helps...............

8 0
3 years ago
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