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ehidna [41]
3 years ago
11

9 batteries cost 18 dollars what's the rate and unit rate

Mathematics
1 answer:
Vanyuwa [196]3 years ago
8 0
Answer to your question is 2
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What is 1,289,845 rounded to the nearest ten thousand?
myrzilka [38]
1,290,845 

hope this helps if not just let me know

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3 years ago
What is the rational number between 1/16 and 1/12?
In-s [12.5K]
1/2 (1/16 + 1/12)
1/2 ((3 + 4 )/48)
1/2 × 7/48
= 7/96
7 0
3 years ago
A rectangular area is to be enclosed by a wall on one side and fencing on the other three sides. If 18 meters of fencing are use
Rashid [163]

Answer:

A = L W= 9*\frac{9}{2}=\frac{81}{2} m^2

Step-by-step explanation:

For this case we assume that the total perimeter is 18 ft, we have a wall and the two sides perpendicular to the wall measure x units each one so then the side above measure P-2x= 18-2x.

And we are interested about the maximum area.

For this case since we have a recatangular area we know that the area is given by:

A= LW

Where L is the length and W the width, if we replace from the values on the figure we got:

A(x)= x *(18-2x) = 18x -2x^2

And as we can see we have a quadratic function for the area, in order to maximize this function we can use derivates.

If we find the first derivate respect to x we got:

\frac{dA}{dx} = 18-4x=0

We set this equal to 0 in order to find the critical points and for this case we got:

18-4x=0

And if we solve for x we got:

x=\frac{18}{4}=\frac{9}{2} m

We can calculate the second derivate for A(x) and we got:

\frac{d^2 A}{dx^2}= -4

And since the second derivate is negative then the value for x would represent a maximum.

Then since we have the value for x we can solve for the other side like this:

L= 18-2x = 18-2 \frac{9}{2}= 18-9 =9m

And then since we have the two values we can find the maximum area like this:

A = L W= 9*\frac{9}{2}=\frac{81}{2} m^2

8 0
3 years ago
What are the new<br> coordinates of (6,-2) with<br> the dilation scale factor of<br> 1/2.
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Answer:

(3, - 1 )

Step-by-step explanation:

Assuming the dilatation is centred at the origin then multiply each coordinate by \frac{1}{2}

(6, - 2 ) → (6 × \frac{1}{2}, - 2 × \frac{1}{2} ) → (3, - 1 )

4 0
3 years ago
The incenter of a triangle ________ falls outside of its triangle. A.always B.sometimes C.never
Tju [1.3M]
<span>A.always hope this helps

</span>
3 0
3 years ago
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