Answer:
<h2>1. subtract 3x, subtract 4, divide by -4</h2><h2 /><h2>2. add x</h2>
Step-by-step explanation:
1 + 3x = -x + 4.
subtract 3x
1 = -4x + 4
subtract 4
-3 = -4x
divide by -4
(-3)/(-4) = (4x)/(-4) ⇌ x = 3/4
-x + 6 = 5 - 3x
subtract 5
-x + 1 = - 3x
add x
1 = -2x
5x+3y=58
5x-3y=22
(3y gets cancelled bc 3y-3y=0, then add 5x with 5x, so you're left with)
10x=80, (divide both sides by 10)
x=8
Now we look for y. So choose one formula from the two (let's say 5x + 3y=58)
Substitute x for 8 so it will look like---- 5(8)+3y=58
Multiply 5*8--- so you get -- 40+3y=58
Subtract 40 from both sides and you're left with 3y=18
divide both sides by 3
you get y=6
In conclusion, x=8 and y=6 hence, (8,6)
<span>These triangles are impossible:
a triangle with sides of 3 inches, 4 inches, and 8 inches
(the longest side is greater than the sum of the other 2 sides)
an obtuse equilateral triangle
(all angles in an </span><span>equilateral triangle are acute)
</span>
<span>a triangle with two right angles
The angles of ALL triangles must sum exactly to 180 degrees. Two right angles sum to 180 degrees so the third angle would have to be zero degrees.
</span>
Answer:
neither
Step-by-step explanation:
<em>Both statements are correct.</em>
If matrix 1 has dimensions (r1, c1) and matrix 2 has dimensions (r2, c2), their product can be formed if c1 = r2. The resulting product matrix will have dimensions (r1, c2).
