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aalyn [17]
3 years ago
7

Point A is located at (2, 6), and D is located at (−4, 10). Find the coordinates of the point that lies halfway between A and D.

(5 points)
(−1, 8)
(3, 2)
(−2, 7)
(−3, 4)
Mathematics
2 answers:
valina [46]3 years ago
8 0

(( \frac{1}{2} (( - 4) - 2) + 2and( \frac{1}{2} (10 - 6)) + 6
the answer is(-1,8)
Ede4ka [16]3 years ago
5 0

Answer:

Option A- (-1,8)    

Step-by-step explanation:

Given : Point A is located at (2, 6), and D is located at (−4, 10).

To find : The coordinates of the point that lies halfway between A and D.  

Solution : Let Point A (x_1,y_1)=(2,6) and Point D(x_2,y_2)=(-4,10)

Let the point B lies halfway between A and D.

Formula to find the coordinates of the mid point B between A and D is

B=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

Substitute the value,

B=(\frac{2+(-4)}{2},\frac{6+10}{2})

B=(\frac{-2}{2},\frac{16}{2})

B=(-1,8)

Therefore, Option A

The coordinates of the point B is (-1,8).

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3. The backyard of a home is a rectangle 25m by 30m. A garden of uniform width is to be
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The width of the garden is approximately 3.987 meters

Part B

Please find attached the drawing of the solution

Step-by-step explanation:

Part A

The given parameters are;

The dimensions of the backyard of the home = 25 m by 30 m

The width of the garden to be built in the yard = Uniform width

The shape of the grass left inside = Rectangular

The area of the grass at the center = The area of the garden

Let 'x' represent the width of the garden, we have;

The length of the rectangular grass area at the center, l = 30 - 2·x

The width of the rectangular area of grass at the center, w = 25 - 2·x

The area of the rectangular backyard, A = 30 m × 25 m = 750 m²

The area of the rectangular backyard, A = (The area of the garden) + (The area of the rectangle of grass inside)

The area of the rectangle of grass, GA = (30 - 2·x)·(25 - 2·x) = The area of the garden

The area of the rectangular backyard, A = 750 = (30 - 2·x)·(25 - 2·x) + (30 - 2·x)·(25 - 2·x)  = 2 × (30 - 2·x)·(25 - 2·x) = 8·x² - 220·x + 1,500

∴ 750 = 8·x² - 220·x + 1,500

8·x² - 220·x + 1,500 - 750 = 0

8·x² - 220·x + 750 = 0

x = (220 ± √(220² - 4 × 8 × 750))/(2 × 8)

x ≈ 23.513, or x = 3.987

When x = 25.513, the width of the rectangle of grass inside, w = 25 - 2 × 23.513 = -22.026, which is not a natural (physically possible)

Therefore, the possible width of the garden, x ≈ 3.987

Part B

The drawing of the solution created with MS Visio is attached

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