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gavmur [86]
2 years ago
6

Diane flipped a coin 600 times and it landed heads up 240 times. What is the relative frequency of the coin landing heads up bas

ed on the results of this experiment?
4%
6%
40%
60%
Mathematics
2 answers:
In-s [12.5K]2 years ago
6 0

Answer:

40%

Step-by-step explanation:

Flips 600 times, that's the total flips. ###/600

Heads flipped 240 times, and that's what you're looking for. 240/600

240/600 simplified is 2/5 (0.4)

You're looking for a frequency/percentage so you're looking at the decimal

Decimal number = Percentage

So it'll be 40%

Nina [5.8K]2 years ago
6 0

Answer:c

Step-by-step explanation:took the test

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Deion divided 1/2 of a liter of plant fertilizer evenly among some smaller bottles. He put 1/8 of a liter into each bottle. How
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Answer:

4 bottles

Step-by-step explanation:

Given

Fertilizer = \frac{1}{2}L

Bottles = \frac{1}{8}L

Required

Determine the number of bottles

Represent the number of bottles with N

<em>This implies that N bottles of </em>\frac{1}{8}L<em> fit into </em>\frac{1}{2}L<em> of fertilizer. The relationship between them is:</em>

<em></em>Fertilizer =  Bottles * N

\frac{1}{2}L = \frac{1}{8}L* N

\frac{1}{2} = \frac{1}{8}* N

Multiply through by 8

8 * \frac{1}{2} = 8 * \frac{1}{8}* N

4 = 1* N

4 = N

N = 4

<em>Hence, there are  N = 4</em>

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A 2003 study of dreaming found that out of a random sample of 106 ​people, 80 reported dreaming in color.​ However, the rate of
Vlad [161]

Answer:

Step-by-step explanation:

Hello!

You have the following experiment, a random sample of 106 people was made and they were asked if they dreamed in color. 80 persons of the sample reported dreaming in color.

The historical data from the 1940s informs that the population proportion of people that dreams in color is 0.21(usually when historical data is given unless said otherwise, is considered population information)

Your study variable is a discrete variable, you can define as:

X: Amount of people that reported dreaming in colors in a sample of 106.

Binomial criteria:

1. The number of observation of the trial is fixed (In this case n = 106)

2. Each observation in the trial is independent, this means that none of the trials will have an effect on the probability of the next trial (In this case, the fact that one person dreams in color doesn't affect or modify the probability of the next one dreaming in color)

3. The probability of success in the same from one trial to another (Or success is dreaming in color and the probability is 0.21)

So X~Bi(n;ρ)

In order to be able to run a proportion Z-test you have to apply the Central Limit Theorem to approximate the distribution of the sample proportion to normal:

^ρ ≈ N(ρ; (ρ(1-ρ))/n)

With this approximation, you can use the Z-test to run the hypothesis.

Now what the investigators want to know is if the proportion of people that dreams in color has change since the 1940s, so the hypothesis is:

H₀: ρ = 0.21

H₁: ρ ≠ 0.21

α: 0.10

The test is two-tailed,

Left critical value: Z_{\alpha/2} = Z_{0.95} = -1.64

Right critical value: Z_{1-\alpha /2} = Z_{0.95} = 1.64

If the calculated Z-value ≤ -1.64 or ≥ 1.64, the decision is to reject the null hypothesis.

If -1.64 < Z-value < 1.64, then you do not reject the null hypothesis.

The sample proportion is ^ρ= x/n = 80/106 = 0.75

Z= <u>     0.75 - 0.21    </u> = 12.83

    √[(0.75*0.25)/106]

⇒Decision: Reject the null hypothesis.

p-value < 0.00001 is less than 0.10

If you were to conduct a one-tailed upper test (H₀: ρ = 0.21 vs H₁: ρ > 0.21) with the information of this sample, at the same level 10%, the critical value would be Z_{0.90}1.28 against the 12.83 from the Z-value, the decision would be to reject the null hypothesis (meaning that the proportion of people that dreams in colors has increased.)

I hope this helps!

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