All categories

3 years ago

How do I find the factor of the trinomial of y^2+7y-30

1 answer:

wel3 years ago

7 0

Find two numbers that multiply to -30 (last term) and add to 7 (middle coefficient)

The two numbers are 10 and -3
10 times -3 = -30
10 plus -3 = 7

Using those two values gets us the two factors (y+10) and (y-3)

Therefore, y^2+7y-30 factors to (y+10)(y-3)

The equation y^2+7y-30 = (y+10)(y-3) is true for all values of y.

You might be interested in

When graphed, the circle with equation

Andrei [34K]

Answer:

the correct answer is C

Step-by-step explanation:

3 0

2 years ago

DFG and JKL are complementary angles. M DFG = x+5 and m JKL=x-9. The measure of DFG is ___, and the measure of JKL is ___.

jeyben [28]

Answer:

Step-by-step explanation:

the sum of complementary angles = 90°, hence

x + 5 + x - 9 = 90

2x - 4 = 90 ( add 4 to both sides )

2x = 94 ( divide both sides by 2 )

x = 47

Thus ∠DFG = 47 + 5 = 52° and ∠JKL = 47 - 9 = 38°

6 0

2 years ago

Read 2 more answers

15% of people on the beach do not wear sun screen. If 30 people don't wear sunscreen, what is the total number of people at the

lara [203]

Answer: The information you are given shows that 15% = 30. Multiply 30 by 6 and 2/3 (The number of times 15 goes into 100) and you have your answer. There are 200 people on the beach.

6 0

2 years ago

Multiply (x-1)(x³+4x²+4x-1) and combine like terms. Explain how you reached your answer.

Hitman42 [59]

Answer:

x⁴+3x³ -5x +1

Step-by-step explanation:

To multiply this we are going to <u>multiply each term of the binomial by each term of the polynomial.</u>

$(x-1)(x^{3}+4x^{2} +4x-1)\\=x^4+4x^3+4x^2-x -x^3-4x^2-4x+1$

Now we are going to <u>combine like terms (this means we are going to sum up terms with the same exponent)</u>

$x^4+4x^3+4x^2-x -x^3-4x^2-4x+1 = x^4 +(4x^3-x^3)+(4x^2-4x^2)+(-x-4x)+1\\=x^4+3x^3-5x+1$

Thus, the answer is x⁴+3x³ -5x +1

5 0

2 years ago

Please do this question

crimeas [40]

It would be 16 more 6th graders that are not in either band or orchestra.
15 6th Graders in band
9 6th Graders in both classes
+18 6th Graders in orchestra
-----
42 6th Graders in either class

100 6th Graders in total
-42 6th Graders in either class
-------
58 6th Graders in neither class
58-42= 16 more 6th Graders that are not in either class
You're welcome :)

7 0

2 years ago