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2 years ago

Given a function where one x-intercept of a parabola is (-4,0), what will be the new x-intercept if h is increased by 6?

Mathematics

1 answer:

Ilia_Sergeevich [38]2 years ago

5 0

the answer to your question is 2

You might be interested in

A number is multiplied by 3. if 2 is added to the product you get 17. what is the number

Sveta_85 [38]

The answer is 5
$5 \times 3 = 15 \\ 15 + 2 = 17$

4 0

3 years ago

VEEL

Andre45 [30]

Answer:

$a_n=-3(3)^{n-1}$ ; {-3,-9, -27,- 81, -243, ...}

$a_n=-3(-3)^{n-1}$ ; {-3, 9,-27, 81, -243, ...}

$a_n=3(\frac{1}{2})^{n-1}$ ; {3, 1.5, 0.75, 0.375, 0.1875, ...}

$a_n=243(\frac{1}{3})^{n-1}$ ; {243, 81, 27, 9, 3, ...}

Step-by-step explanation:

The first explicit equation is

$a_n=-3(3)^{n-1}$

At n=1,

$a_1=-3(3)^{1-1}=-3$

At n=2,

$a_2=-3(3)^{2-1}=-9$

At n=3,

$a_3=-3(3)^{3-1}=-27$

Therefore, the geometric sequence is {-3,-9, -27,- 81, -243, ...}.

The second explicit equation is

$a_n=-3(-3)^{n-1}$

At n=1,

$a_1=-3(-3)^{1-1}=-3$

At n=2,

$a_2=-3(-3)^{2-1}=9$

At n=3,

$a_3=-3(-3)^{3-1}=-27$

Therefore, the geometric sequence is {-3, 9,-27, 81, -243, ...}.

The third explicit equation is

$a_n=3(\frac{1}{2})^{n-1}$

At n=1,

$a_1=3(\frac{1}{2})^{1-1}=3$

At n=2,

$a_2=3(\frac{1}{2})^{2-1}=1.5$

At n=3,

$a_3=3(\frac{1}{2})^{3-1}=0.75$

Therefore, the geometric sequence is {3, 1.5, 0.75, 0.375, 0.1875, ...}.

The fourth explicit equation is

$a_n=243(\frac{1}{3})^{n-1}$

At n=1,

$a_1=243(\frac{1}{3})^{1-1}=243$

At n=2,

$a_2=243(\frac{1}{3})^{2-1}=81$

At n=3,

$a_3=243(\frac{1}{3})^{3-1}=27$

Therefore, the geometric sequence is {243, 81, 27, 9, 3, ...}.

6 0

3 years ago

Helen had Php7500 for shopping money. When she got home, she had Php132.75 in her pocket. How much did she spend for shopping?

Nataly_w [17]

Answer:

Step-by-step explanation:

Helen had Php7500 for shopping money

she had Php132.75 in her pocket

she spend= 7500.00-132.75

=7367.25answer

4 0

3 years ago

Eric scored 95% on his math test. He got 19 problems correct. How many questions were on the test?

Leviafan [203]

i'm pretty sure it's 20.

8 0

2 years ago

Which function models the area of a rectangle with side lengths of 2x - 4 units and x + 1 units?

aalyn [17]

Answer:

Area of rectangle, $f(x)=2x^2-2x-4$ .

Step-by-step explanation:

We are given with side lengths of a rectangle are (2x-4) units and (x+1) units. It is required to find the area of rectangle.

The area of a rectangle is equal to the product of its length and breadth. It is given by :

$A=L\times B$

Let us consider, L = (2x-4) units and B = (x+1) units

Plugging the side lengths in above formula:

$A=(2x-4)\times (x+1)$

$A=2x^2+2x-4x-4\\\\A=2x^2-2x-4$

So, the function that models the area of a rectangle is $f(x)=2x^2-2x-4$ .

5 0

2 years ago