The area of a square is the square of the length of its side. Here, we're told that the side of each square is equal to the radius (r) of the circle. Then the area of each square is
.. Asquare = r^2
There are 3 of them, so their total area is
.. Aall_squares = 3*r^2
The area of a circle is given by the formula
.. Acircle = π*r^2 . . . . . where r represents the radius of the circle
Fernie wants to compare the area of the 3 squares to that of the circle. We know that the value of π is about 3.1416, a little more than 3, so we have
.. Aall_squares = 3*r^2
.. Acircle ≈ 3.1416*r^2
We notice that 3.1416 is more than 3, so the area of the circle is greater than the area of Fernie's 3 squares.
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It is not clear to me that Fernie's drawing will explain the formula A = π*r^2, unless it can somehow be used to show that the parts of each square that are outside the circle add up to an amount that is slightly less than the uncovered part of the circle.
Answer:
C
Step-by-step explanation:
I did the math
Answer:
3
Step-by-step explanation:
Range is the largest number minus the smallest number
4-1 = 3
The range is 3
Problem 1
The largest value would be 1 and the smallest would be
-1.
To get a product of 1, either all are 1 or two of the
variables are -1 and the other one is 1.
Largest value = (1)^2 * (1)^3 * (1)^4 =1
Smallest value = (- 1)^2 * (- 1)^3 * (1)^4 = -1
The difference is:
largest value – smallest value = 1 – (-1) = 2
<span>Therefore the answer is letter D.</span>
Problem 2
% loss = (final price – initial price) * 100%/ initial
price
where, final price per dozen = ( $2.50 / piece) (12 piece
/ dozen) = $30
Therefore,
% loss = ($30 - $33) * 100 / $33
% loss = - 300/ 33 = 9 1/11
<span>Therefore the answer is <span>letter C.</span></span>
