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Alchen [17]
2 years ago
12

What is the calculation of

rmula1" title="2 5 \6 - (4 1 \3 - 3 \2)" alt="2 5 \6 - (4 1 \3 - 3 \2)" align="absmiddle" class="latex-formula">
​

Mathematics
1 answer:
shepuryov [24]2 years ago
8 0

<h3><u>25</u> ( <u>13</u><u> </u> - <u>3</u><u>)</u></h3><h3> 6 ( 3 2)</h3>

<u>25</u><u> </u><u> </u>( <u>39 -9)</u>

6 (6)

<u>2</u><u>5</u><u> </u> × <u>30</u>

6 6

<u>125</u>

6

20 <u> 5</u><u> </u><u> </u> [ans]

6

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Solve for x. Round your answer to the nearest hundredth.<br> 2x^2-6x+3=0
pogonyaev

Step-by-step explanation:

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A real estate sales agent receives a salary of $250 per week plus a commission of 2% of sales.Write an equation that gives the w
lisabon 2012 [21]

The equation y=0.02x+250 gives the weekly income y in terms of sales x.

Step-by-step explanation:

Given,

Weekly salary of real estate agent = $250

Commission rate = 2%

Let,

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y be the total weekly income.

Amount of commission = 2% of sales per week

Amount of commission = \frac{2}{100}*x

Amount of commission = 0.02x

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The equation y=0.02x+250 gives the weekly income y in terms of sales x.

Keywords: equation, percentage

Learn more about percentages at:

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3 years ago
What is 13.989 to the nearest hundredth place?
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Answer:

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Step-by-step explanation:

So the hundredths place is the second digit after the decimal point in this case it is 8.

So the number after it is 9 so we round up.

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3 years ago
What is the probability of rolling a number greater than or equal to 9 with the sum of two dice, given that at least one of the
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Conditional probablility P(A/B) = P(A and B) / P(B). Here, A is sum of two dice being greater than or equal to 9 and B is at least one of the dice showing 6. Number of ways two dice faces can sum up to 9 = (3, 6), (4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 10 ways. Number of ways that at least one of the dice must show 6 = (1, 6), (2, 6), (3, 6), (4, 6), (5, 6), (6, 6), (6, 5), (6, 4), (6, 3), (6, 2), (6, 1) = 11 ways. Number of ways of rolling a number greater than or equal to 9 and at least one of the dice showing 6 = (3, 6), (4, 6), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 7 ways. Probability of rolling a number greater than or equal to 9 given that at least one of the dice must show a 6 = 7 / 11
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3 years ago
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