Answer:
given a quadratic function, y = ax2 + bx + c, when "a" is positive, the parabola opens upward and the vertex is the minimum value. On the other hand, if "a" is negative, the graph opens downward and the vertex is the maximum value
Step-by-step explanation:
Solution:
Given:
<u>Substitute the values into the equation:</u>
- x⁶ - x/4y
- => [(-4)⁶] - (-4)/4(4)
<u>Simplify the numerator and the denominator:</u>
- => [(-4) x (-4) x (-4) x (-4) x (-4) x (-4)] + 4/16
- => [(-64) x (-64)] + 4/16
- => [4096] + 4/16
- => 4100/16
<u>Simplify the fraction:</u>
- => 4100/16
- => 1025 x 4/4 x 4
- => 1025/4
Correct option is B.
None of the other answers are correct. If there is an answer C, it would probably be that answer.
Answer:
-5, 5
Step-by-step explanation:
The line in this problem can be written in the form
(1)
where:
is the slope
q is the y-intercept
We know that the line passes through the point (-2,5), so substituting these values into eq.(1), we find the value of the y-intercept:
So the equation of the line is
(2)
Now we know that point A has coordinates
A(x,3)
So by substituting into eq.(2), we find the missing x-coordinate:
Similarly, point B has coordinates
B(-2,y)
so substituting into eq(2), we find the missing y-coordinate:
6cm and create a key say it’s supposed to be km