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erik [133]
3 years ago
9

Online customer service is a key element to successful online retailing. According to a marketing survey, 37.5% of online custom

ers take advantage of the online customer service. Random samples of 200 customers are selected.
a) What is the population mean of all possible sample proportions?

b) What is the standard error of all possible sample proportions?

c) What percent of the samples are likely to have between 35% and 40% who take advantage of online customer service?

d) What percent of the samples are likely to have less than 37.5% who take advantage of online customer service?

e) Please fill-in the blanks: 95% of the samples proportions symmetrically around the population proportion will have between ________% and ________% of the customers who take advantage of online customer service.
Mathematics
1 answer:
exis [7]3 years ago
5 0

Answer:

no

Step-by-step explanation:

I am not sure about this bout you can do it

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Answer:

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Step-by-step explanation:

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3 years ago
1/2x + 6= 3x - 4<br> Solve the system of equations
shepuryov [24]
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3 years ago
Please help me asap !!
LUCKY_DIMON [66]
The answer is choice A

The line is RS because R and S are on the line. 

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3 years ago
When you divide a whole number by a decimal less than 1, the quotient is greater than the whole number. why?
Viktor [21]
Well if you get back to the definition of a division, diving X by Y is finding out how many Ys you can have in a X.

It is clear that you will have more than X times Y if Y is less than 1 since dividing X by 1 is exactly X.

If you think of 10 and 1, you can divide 10 in exactly 10 portions of 1.
But you can divide it into 100 portions of 0,1.
And 100 is bigger than 10 of course.
Hope this helps.
4 0
3 years ago
Read 2 more answers
Can Someone Tell Me If I will Pass My 7th Period With The Grades I Have for semester 1 A+M1, BT1, FM2, DT2, FSemExam, C+S1 Grade
ASHA 777 [7]

Answer

If u fail the 3 main courses math, ela, and social studies you would fail, but two F's I dont think ur going to fail good luck though

Step-by-step explanation:

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