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Anika [276]
3 years ago
8

Using the numbers 3, 2, and 4, which of these problems would have a solution of 4?

Mathematics
1 answer:
Alexeev081 [22]3 years ago
7 0
Pemdas

ok if we look at the first one
exponents first
2^3=8
2^3=8
we have
4*8/8
4*8=32
32/8=4
das is answer


the first one is the answer
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Haley’s work evaluating (Negative 2) Superscript 8 is shown below.
PSYCHO15rus [73]

Answer:

D

Step-by-step explanation:

<em>The statements are shown below:</em>

<em>A) She used the wrong number as a repeated factor and should have evaluated -2x2x2x2x2x2x2x2. </em>

<em>B) She used the wrong number as a repeated factor and should have evaluated -(8x8). </em>

<em>C) She misinterpreted the exponential form and should have multiplied -2 and 8. </em>

<em>D) She made a sign error when multiplying and should have had 256 as a final answer.</em>

<em />

<u>Solution:</u>

<u />

The problem to simplify is:

(-2)^{8}

Haley's steps are shown below:

(-2)^{8}=(-2)(-2)(-2)(-2)(-2)(-2)(-2)(-2)=-256

Generally,

(a)^b  is actually "a" multiplied "b" times.

So, Haley wrote "-2" eight times multiplied together. That is okay.

Now,

We are dealing with negative numbers.

  • When negative numbers are multiplied "odd" number of times, the answer is negative.
  • When negative numbers are multiplied "even" number of times, the answer is positive.

Haley wrote "-2" eight times, which is EVEN number of times, so the answer would be POSITIVE. But, Haley's answer is negative. Which is wrong. But "256" is right.

Haley's error is:

Answer choice D

6 0
3 years ago
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or d=15+q

I believe this is how you do it

Step-by-step explanation:

5 0
3 years ago
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