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Anika [276]
4 years ago
8

Using the numbers 3, 2, and 4, which of these problems would have a solution of 4?

Mathematics
1 answer:
Alexeev081 [22]4 years ago
7 0
Pemdas

ok if we look at the first one
exponents first
2^3=8
2^3=8
we have
4*8/8
4*8=32
32/8=4
das is answer


the first one is the answer
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Answer: 
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The roots of the given polynomials exist  $x=8+\sqrt{10}$, and $x=8-\sqrt{10}$.

<h3>What is the formula of the quadratic equation?</h3>

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simplifying the equation, we get

$&x_{1,2}=\frac{-(-16) \pm 2 \sqrt{10}}{2 \cdot 1} \\

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3 years ago
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