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Anika [276]
4 years ago
8

Using the numbers 3, 2, and 4, which of these problems would have a solution of 4?

Mathematics
1 answer:
Alexeev081 [22]4 years ago
7 0
Pemdas

ok if we look at the first one
exponents first
2^3=8
2^3=8
we have
4*8/8
4*8=32
32/8=4
das is answer


the first one is the answer
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<em>Given</em><em>,</em>

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<em>=</em><em> </em><em>-</em><em>4</em><em> </em><em>(</em><em> </em><em>-c </em><em>+</em><em> </em><em>8</em><em> </em><em>)</em><em> </em><em>-</em><em> </em><em>(</em><em>3</em><em>c</em><em> </em><em>+</em><em> </em><em>7</em><em> </em><em>)</em>

<em>=</em><em> </em><em>4</em><em>c</em><em> </em><em>-</em><em> </em><em>3</em><em>2</em><em> </em><em>-</em><em> </em><em>(</em><em> </em><em>3</em><em>c</em><em> </em><em>+</em><em> </em><em>7</em><em> </em><em>)</em>

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