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liubo4ka [24]
4 years ago
10

Complete the square to determine the maximum or minimum value of the function defined by the expression. x2 − 6x + 5 A) minimum

value at 5 B) maximum value at 4 C) minimum value at −4 D) maximum value at −5
Mathematics
2 answers:
myrzilka [38]4 years ago
7 0

y=ax^2+bx+c\to y=x^2-6x+5

a = 1 > 0 therefore, this function has minimum.

Use (*)\ (a-b)^2=a^2-2ab+b^2

x^2-6x+5=x^2-2\cdot x\cdot3+5=\underbrace{x^2-2\cdot x\cdot3+3^2}_{(*)}-3^2+5\\\\=(x-3)^2-9+5=(x-3)^2-4

Answer: C) minimum value at −4.

ivanzaharov [21]4 years ago
5 0

Answer: C

Step-by-step explanation: trust me it's right

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Step-by-step explanation:

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8 0
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Find tan B. AB=17,BC=15 AC= 8
Aneli [31]

Answer:

a is the ans;8/15

Step-by-step explanation:

we have tanb = p/ b

so,by taking reference angle b we get,

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5 0
4 years ago
How do I solve this equation 10(x+2)>-2(6-9x)?
Norma-Jean [14]
Use distributive property for each side of the equation
1.) 10(x+2)>-2(6-9x)
2. 10x + 20> -12+18x

Then whatever you do to one side of the equation, you do to the other. So we’re trying to get x alone on one side.
Subtract 10x from each side
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3 0
3 years ago
Read 2 more answers
2 PUNTS
xz_007 [3.2K]

Answer:

x^2  +  y^2  = 4

Step-by-step explanation:

The center-radius form (formally called the standard form) of a circle is

(x-h)^2+(y-k)^2=r^2 where (h,k) is the center and r is the radius.

So if we replace (h,k) with (0,0) since the center is the origin and r with 2 since the radius is 2 we get:

(x-0)^2+(y-0)^2=2^2

Let's simplify:

x^2  +  y^2   = 4

8 0
3 years ago
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