Answer:
20. 
22. 
24. 
Step-by-step explanation:
20. 
The GCF is x, so you group it out of the equation first.
Then, you find 2 numbers that will equal to 2 when you add them and will equal to -48 when you multiply them.
The two numbers would be -6 and 8. You then differentiate the squares.
22. 
The GCF is 2, so you must group it out.
Find the two numbers that will equal to 5 when you add them and will equal to 4 when you multiply them.
The two numbers would be 1 and 4. Finally, differentiate the squares.
24. 
The GCF is 5m, so you must group it out.
Find the two numbers that will equal to 6 when you add them and will equal to -7 when you multiply them.
The two numbers would be -1 and 7. Finally, differentiate the squares.
Answer:
The correct option is;
A. You don't have ABS
Step-by-step explanation:
A car braking system works by the friction action the break pad applies on the wheels, when the break is applied with much force, due to hard and sudden breaking of the motion of the vehicle, the break pad stops the rotation of the wheels but the vehicle could however continue skidding due to the high initial momentum
The being skidding vehicle in a situation of kidding increases the likelihood for an accident as the the vehicle can no longer be controlled at the steering either
Threshold braking is the technique of bringing the vehicle to a stop or slowing down in the shortest time possible by applying an optimum breaking force during breaking
Anti-lock Braking System is a safety feature that prevents skidding by keeping the wheels of the vehicle or aircraft from locking when excessive break is applied such that traction maintained between the wheels and the road.
Answer: stop pay attention in class
Step-by-step explanation:
This is an exponential equation. We will solve in the following way. I do not have special symbols, functions and factors, so I work in this way
2 on (2x) - 5 2 on x + 4=0 =>. (2 on x)2 - 5 2 on x + 4=0 We will replace expression ( 2 on x) with variable t => 2 on x=t =. t2-5t+4=0 => This is quadratic equation and I solve this in the folowing way => t2-4t-t+4=0 => t(t-4) - (t-4)=0 => (t-4) (t-1)=0 => we conclude t-4=0 or t-1=0 => t'=4 and t"=1 now we will return t' => 2 on x' = 4 => 2 on x' = 2 on 2 => x'=2 we do the same with t" => 2 on x" = 1 => 2 on x' = 2 on 0 => x" = 0 ( we know that every number on 0 gives 1). Check 1: 2 on (2*2)-5*2 on 2 +4=0 => 2 on 4 - 5 * 4+4=0 => 16-20+4=0 =. 0=0 Identity proving solution.
Check 2: 2 on (2*0) - 5* 2 on 0 + 4=0 => 2 on 0 - 5 * 1 + 4=0 =>
1-5+4=0 => 0=0 Identity provin solution.
