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Vinil7 [7]
3 years ago
8

A building has a ramp to its front doors to accommodate the handicapped. If the distance from the building to the end of the ram

p is 22 feet and the height from the ground to the front doors is 5 feet, how long is the ramp?
Mathematics
1 answer:
bija089 [108]3 years ago
7 0
<span>The ramp forms a right triangle with legs 5 and 22. 
 Find the length of the hypotenuse using the Pythagorean theorem,
 c=raiz((5)^2+(22)^2)=</span><span> <span>22.56 ft
 Answer
</span></span> the ramp is 22.56 ft long. 
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Answer:

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Step-by-step explanation:

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2 years ago
What is 3(5x^2-9x) evaluated for x=-3
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216

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If sinA=√3-1/2√2,then prove that cos2A=√3/2 prove that
Ivan

Answer:

\boxed{\sf cos2A =\dfrac{\sqrt3}{2}}

Step-by-step explanation:

Here we are given that the value of sinA is √3-1/2√2 , and we need to prove that the value of cos2A is √3/2 .

<u>Given</u><u> </u><u>:</u><u>-</u>

• \sf\implies sinA =\dfrac{\sqrt3-1}{2\sqrt2}

<u>To</u><u> </u><u>Prove</u><u> </u><u>:</u><u>-</u><u> </u>

•\sf\implies cos2A =\dfrac{\sqrt3}{2}

<u>Proof </u><u>:</u><u>-</u><u> </u>

We know that ,

\sf\implies cos2A = 1 - 2sin^2A

Therefore , here substituting the value of sinA , we have ,

\sf\implies cos2A = 1 - 2\bigg( \dfrac{\sqrt3-1}{2\sqrt2}\bigg)^2

Simplify the whole square ,

\sf\implies cos2A = 1 -2\times \dfrac{ 3 +1-2\sqrt3}{8}

Add the numbers in numerator ,

\sf\implies cos2A =  1-2\times \dfrac{4-2\sqrt3}{8}

Multiply it by 2 ,

\sf\implies cos2A = 1 - \dfrac{ 4-2\sqrt3}{4}

Take out 2 common from the numerator ,

\sf\implies cos2A = 1-\dfrac{2(2-\sqrt3)}{4}

Simplify ,

\sf\implies cos2A =  1 -\dfrac{ 2-\sqrt3}{2}

Subtract the numbers ,

\sf\implies cos2A = \dfrac{ 2-2+\sqrt3}{2}

Simplify,

\sf\implies \boxed{\pink{\sf cos2A =\dfrac{\sqrt3}{2}} }

Hence Proved !

8 0
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Answer:

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4 0
3 years ago
The diameter of a circle is 15 ft. Find its circumference in terms of \piπ.
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