Find the roots of the equation: y=4(X+4)^2 -12

1 answer:

3 0

0=4(x²+8x+16)-12
0=4x²+32x+64-12
0=4x²+32x+52
0=x²+8x+13
D=b²-4ac
D=64-52=12
x=(-b-√D)/2a
x=(-b+√D)/2a
x=(-8-2√3)/2= (-2(4+√3))/2= -(4+√3)
AND
x=(-8+2√3)/2=-2(4-√3)/2= -(4-√3)

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