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pishuonlain [190]
3 years ago
12

Thanh and her crew are building a stage in the shape of a trapezoid for an upcoming festival. The lengths of the parallel sides

of the trapezoid are 14 ft and 24 ft. The height of the trapezoid is 12 ft. What is the area of the stage?
Mathematics
1 answer:
Xelga [282]3 years ago
8 0

Answer: The answer would be 228. (:

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Please help <br><br>the question is beloww
madam [21]

Answer:

-8

Step-by-step explanation:

(x-3y=136) + (18x+3y=288) We collect both processes to make y's disappear

19x=-152

x=-8

5 0
3 years ago
Find the distance (8,-7) (-4,-2)
Vinil7 [7]

Distance = 13 units

Point A: (8, -7)

Point B: (-4, -2)

\sqrt{(8 + 4)^{2} + (-7 + 2)^{2} }

\sqrt{(12)^{2} + (-5)^{2} }

\sqrt{144 + 25 }

\sqrt{169}

13

7 0
3 years ago
Read 2 more answers
X^2 + Y^2 +ax + 2y + 3 = 0<br><br> What number is this equation the equation of a circle?
Sav [38]

Answer:

Eq: (x+a/2)²+(y+1)²=(a²-8)/4

Center: O(-a/2, -1)

Radius: r=0.5×sqrt(a²-8)

Mandatory: a>2×sqrt(2)

Step-by-step explanation:

The circle with center in O(xo,yo) and radius r has the equation:

(x-xo)²+(y-yo)²=r²

We have:

x²+y²+ax+2y+3=0

But: x²+ax=x²+2(a/2)x+a²/4-a²/4= (x+a/2)²-a²/4

And

y²+2y+3=y²+2y+1+2=(y+1)²+2

Replacing, we get:

(x+a/2)²-a²/4+(y+1)²+2=0

(x+a/2)²+(y+1)²=a²/4-2=(a²-8)/4

By visual inspection we note that:

- center of circle: O(-a/2, -1)

- radius: r=sqrt((a²-8)/4)=0.5×sqrt(a²-8). This means a²>8 or a>2×sqrt(2)

6 0
3 years ago
What’s 18.938+23.57 to the nearest whole number
horsena [70]

Answer: 43

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Solve both by elimination can someone help?<br> 2x-5y=-9 , 4x+5y=12<br><br> 3x-2y=12 , 7x-5y=17
lyudmila [28]

Answer:

x=1/2, y=2;    

Step-by-step explanation:

First pair:

2x-5y =-9

4x+5y=12

Add them together:

6x=3

x = 1/2

2(1/2) - 5y =-9

1-5y = -9

1+9=5y

y=10/5=2

8 0
2 years ago
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