The probable genotype of the IV-3 with the perspective of autosomal inheritance will be A because he does not have condition A. Therefore both parents must be in condition A.
The probable genotype of IV-3 with the perspective of set=linked inheritance will be BbY this is because he has B condition. Therefore the mothers' genotype must be XBXb and the father's genotype must be XBY.
The probability of IV-4 having condition A is 1/36
In this case, c) mimicry is the answer. In Batesian mimicry in which harmless animals mimic toxic animals. In this case, I assume the milk snake is harmless and the coral snake is venomous. Since the milk snake has a trait similar to deadly coral snake, less animals would eat it thinking it is dangerous. Over time all the milk snake that look like the deadly coral snake would survive leading to evolution by natural selection. This would lead to more and more milk snake mimicking the resemblance of the deadly coral snake.
a) The deadly coral snake has a warning color adaptive radiation. If the question had described the environment and how the snaked adapted to the environment via warning coloration. This would've been correct.
b) cryptic coloration is more about camouflage with the environment. If the question had state how a certain feature help one of the animals blend into the background. This would've been correct.
d) I'm not sure whats different between this and a so i'll consider them both the same.
I think the answer is C and D
