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Whitepunk [10]
3 years ago
14

How does cells get to your body?

Biology
2 answers:
Flura [38]3 years ago
6 0
DNA should be the correct answer
katovenus [111]3 years ago
5 0

Answer: body tissue

Explanation:

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According to the dichotomous key, stentor would be a member of the kingdom
GarryVolchara [31]
The answer is Protista.

The dichotomous key is used to identify the taxonomic category of an organism. So, if we start with statements from the beginning, and discard the possibilities, we can put the organism into some taxonomic group.
Accordingly, we know that a stentor has a nucleus, so it must be eukaryotic. Among the Eukaryotes, it could belong to the kingdom of Protista, Fungi, Plantae and Animalia. Since it is unicellular organism and lives only in the water, it could belong only to the kingdom of Protista
4 0
4 years ago
Why were Domains added to the classification system after the time of Linnaeus?
Luden [163]

Answer: With the development of powerful microscopes, scientists discovered many single-celled organisms that didn't fit into any of Linnaeus' kingdoms. As a result, a new taxon, called the domain, was added to the classification system.

Explanation:

7 0
3 years ago
What blood vessel delivers oxygenated blood to the heart structure that separates the left and right ventricles?
xenn [34]

Answer:

The left side of the heart receives oxygenated blood from the pulmonary vein and pumps it into the aorta, while the right side of the heart receives deoxygenated blood from the vena cava and pumps it into the pulmonary vein. The pulmonary vein and aorta also have valves connecting them to their respective ventricle.

Explanation:

7 0
3 years ago
Which RNA types are involved in translation?
Nezavi [6.7K]
C. Is the answer for sure
4 0
3 years ago
Consider a cell in which Cl- distributes passively across the membrane according to the membrane potential. The resting membrane
UNO [17]

Answer:

1000 mM

Explanation:

Using V = -60 mV㏒₁₀[K/K'] where V = membrane potential = -60 mV, K = intracellular concentration = unknown and K' = extracellular concentration = 100 mM

So, V = -60 mV㏒₁₀[K/K']

-60  mV = -60 mV㏒₁₀[K/K']

dividing both sides by -60mV, we have

-60  mV/-60 mV = ㏒₁₀[K/K']

㏒₁₀[K/K'] = 1

taking antilogarithm of both sides, we have

[K/K']  = 10¹

multiplying both sides by K', we have

K = 10K'

K = 10 × 100 mM

K = 1000 mM

So, the intracellular Cl- concentration is 1000 mM

4 0
3 years ago
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