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Xelga [282]
3 years ago
14

Work out the area of a triangle of base 8.2m and height 5m

Mathematics
2 answers:
11Alexandr11 [23.1K]3 years ago
5 0
Area of a triangle is calculated by using the formula A=1/2bh
A= 1/2 (8.2) (5)
A=1/2 (41)
A=20.5 or 20 1/2, whichever way you think your teacher wants it.
postnew [5]3 years ago
4 0
The area of a triangle is half the base × height. So you multiply 8.2 × 5 to get 41. And when you divide that by 2, you get 20.5
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What value is true of x makes this equation true 0.7x-5=0.2x+1
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Answer:

x=12

Step-by-step explanation:

First you make sure x is on both sides of the equation. So you do 0.7x-5-0.2x=0.2x+1-0.2x. Which just simplifies to 0.5x-5=1. You make sure x is the only thing on that side of the equation so you do 0.5x-5+5=1+5 which simplifies to 0.5x=6. Multiply the equation times 2 to just have x. x=12. The value that makes true of x is 12.

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the ricky family drove 224 miles for a trip to the beach. at lunch they drove 17 miles to the nearest restaurant and later that
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3 years ago
In JKL, k=4.1 cm,j=3.8 cm and angle J=Q3^ Find all possible values of angle K , to the nearest inch of a degree .
spayn [35]

Answer:

74.0°

Step-by-step explanation:

In triangle JKL, k = 4.1 cm, j = 3.8 cm and ∠J=63°. Find all possible values of angle K, to the  nearest 10th of a degree

Solution:

A triangle is a polygon with three sides and three angles. Types of triangles are right angled triangle, scalene triangle, equilateral triangle and isosceles triangle.

Given a triangle with angles A, B, C and the corresponding sides opposite to the angles as a, b, c. Sine rule states that for the triangle, the following holds:

\frac{a}{sin(A)}=\frac{b}{sin(B)}=\frac{c}{sin(C)}

In triangle JKL, k=4.1 cm, j=3.8 cm and angle J=63°.

Using sine rule, we can find ∠K:

\frac{k}{sin(K)}=\frac{j}{sin(J)}   \\\\\frac{4.1}{sin(K)}=\frac{3.8}{sin(63)}  \\\\sin(K)=\frac{4.1*sin(63)}{3.8}\\\\sin(K)=0.9613\\\\K=sin^{-1} (0.9613)\\\\K=74.0^o  \\

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It's known as a heterotroph. They can't make their own food.
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If the perimeter is 90 feet and on side is 26 feet then the width of the playground is 38 feet
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3 years ago
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