Answer:
Let's define the cost of the cheaper game as X, and the cost of the pricer game as Y.
The total cost of both games is:
X + Y
We know that both games cost just above AED 80
Then:
X + Y > AED 80
From this, we want to prove that at least one of the games costed more than AED 40.
Now let's play with the possible prices of X, there are two possible cases:
X is larger than AED 40
X is equal to or smaller than AED 40.
If X is more than AED 40, then we have a game that costed more than AED 40.
If X is less than or equal to AED 40, then:
X ≥ AED 40
Now let's take the maximum value of X in this scenario, this is:
X = AED 40
Replacing this in the first inequality, we get:
X + Y > AED 80
Replacing the value of X we get:
AED 40 + Y > AED 80
Y > AED 80 - AED 40
Y > AED 40
So when X is equal or smaller than AED 40, the value of Y is larger than AED 40.
So we proven that in all the possible cases, at least one of the two games costs more than AED 40.
The direct variation equation is:
d=kt
where d is the distance that the giraffe travels
k is the constant of variation
and t is time
Now we are told that the giraffe can travel 800 ft in 20 seconds, so we can solve for the constant of variation (k)
800=k(20) divide both sides by 20
k=40-------------and the units are ft per sec
So now we can write
d=40t
ck
d=40t
800ft=40*20 ft
800 ft= 800 ft
Hope this helps!
ANSWER
x= 46
EXPLANATION
To solve this problem you need to remember that a straight line is 180°. This figure is basically a straight line split in two, so 134°+x=180°. You can also subtract 134 from 180 to get 46.
Answer:
Any more details?
Step-by-step explanation:
You would set the equations equal to eachother and get x=-5/4 and then plug that in for x, i hope this helps!
