Combine like terms to get -4x^2-2x
Part A:
Given a square with sides 6 and x + 4. Also, given a rectangle with sides 2 and 3x + 4
The perimeter of the square is given by 4(x + 4) = 4x + 16
The area of the rectangle is given by 2(2) + 2(3x + 4) = 4 + 6x + 8 = 6x + 12
For the perimeters to be the same
4x + 16 = 6x + 12
4x - 6x = 12 - 16
-2x = -4
x = -4 / -2 = 2
The value of x that makes the <span>perimeters of the quadrilaterals the same is 2.
Part B:
The area of the square is given by

The area of the rectangle is given by 2(3x + 4) = 6x + 8
For the areas to be the same

Thus, there is no real value of x for which the area of the quadrilaterals will be the same.
</span>
If n is the hypotenuse, then it is 37. L can't be the hypotenuse and if m is the hypotenuse then n is 32.878
Answer:

Step-by-step explanation:
Given
Shapes: Cube and Cone
Required
Determine the volume
First we calculate the volume of the cube

Where
l = side length = 5.1


Next, calculate the volume of the cone using:

Where
h = 5.1



So, we have:





The volume of the figure is:




Answer:
1 9/16
Step-by-step explanation:
F(1/4) means u plug in 1/4 for x
so the equation would be
f(1/4)=1/4^2+2 1/4 + 1
f(1/4)=1/16+1/2+1
f(1/4)= 9/16 +1
f(1/4)= 1 9/16
its not nine teen its one and 9 over 16 just clarification