Answer:
2.35%
Step-by-step explanation:
First, calculate the difference between mean and the months in the problem:
first month :59 – 26 = 33
second motnh: 59 – 37 = 22
Since standard deviation is 11 months, for the first month is a difference of 3 standard deviation and for the second is 2 standard deviation.
the 68-95-99.7% rule establish that:
1 standard deviation means a 68% of total area under the normal distribution. On one side is half = 34%.
2 standard deviations means a 95% of total area under the normal distribution. On one side is half = 47.5%.
3 standard deviation means a 99.7% of total area under the normal distribution. On one side is half = 49.85%.
The difference between 3 and 2 standard deviation is
49.85 – 47.5 = 2.35%
The answer is 2.35% of cars that remain in service between 26 and 37 months
So basically plus likes 21.9+73:5=let’s say 5 than your do 6.5+73.5=“788” then 21.9+6.5=“789” (those aren’t the real answers) you do that and do addition the 3 answers together and Multiple by 2
Lets p = salesman's commission as percent
15,200 * p = 912
p = 912/ 15,200
p = 0.06
p = 6%
answer
6%
Answer:
I'm sorry, I'm not really certain of anything except part A
Step-by-step explanation:
Part A
First of all write the function.
Let x = the number of hours traveled. The y intercept is the value when x = 0
y = 2x + 50 Every 1 hour, the speed increases by 2 mph
(1) The y intercept is 0,50
(2) The car was travelling at 50 mph to begin with.
Part B
Average speed = total distance covered / time interval
Distance between 1 and 2 = 52 + (54 - 52)/1 = 54
Distance between 2 and 3 = 54 + (56 - 54)/1 = 56
Average = (54 + 56)/2 = 55
Part C
I don't see how Part C has any answer. It must change motion even if it winds up where it started from (in which case the velocity cannot be both 60 and 0 at the same time)
I think they want you to answer 0.