Answer:
the third
Step-by-step explanation: because find the area
Part of the value of sin(u) is cut off; I suspect it should be either sin(u) = -5/13 or sin(u) = -12/13, since (5, 12, 13) is a Pythagorean triple. I'll assume -5/13.
Expand the tan expression using the angle sum identities for sin and cos :
tan(u + v) = sin(u + v) / cos(u + v)
tan(u + v) = [sin(u) cos(v) + cos(u) sin(v)] / [cos(u) cos(v) - sin(u) sin(v)]
Since both u and v are in Quadrant III, we know that each of sin(u), cos(u), sin(v), and cos(v) are negative.
Recall that for all x,
cos²(x) + sin²(x) = 1
and it follows that
cos(u) = - √(1 - sin²(u)) = -12/13
sin(v) = - √(1 - cos²(v)) = -3/5
Then putting everything together, we have
tan(u + v)
= [(-5/13) • (-4/5) + (-12/13) • (-3/5)] / [(-12/13) • (-4/5) - (-5/13) • (-3/5)]
= 56/33
(or, if sin(u) = -12/13, then tan(u + v) = -63/16)
Answer:
55 cents
Step-by-step explanation:
9514 1404 393
Answer:
- 32
- 80
Step-by-step explanation:
The equation y = 8x means the value given for x is multiplied by 8.
1. 8 × 4 = 32 . . . scales in 4 days
2. 8 × 10 = 80 . . . scales in 10 days
Answer:
answer is √65
Step-by-step explanation:
Distance=
![\sqrt{(2 - ( - 6) ) ^{2} + (- 3 + 2) ^{2} }](https://tex.z-dn.net/?f=%20%5Csqrt%7B%282%20-%20%28%20-%206%29%20%29%20%5E%7B2%7D%20%20%2B%20%20%28-%203%20%2B%202%29%20%5E%7B2%7D%20%20%7D%20)
distance=
![\sqrt{8 ^{2} + ( - 1) ^{2} }](https://tex.z-dn.net/?f=%20%5Csqrt%7B8%20%5E%7B2%7D%20%2B%20%28%20-%201%29%20%5E%7B2%7D%20%20%7D%20)
distance=
![\sqrt{64 + 1}](https://tex.z-dn.net/?f=%20%5Csqrt%7B64%20%2B%201%7D%20)
distance=
![\sqrt{65}](https://tex.z-dn.net/?f=%20%5Csqrt%7B65%7D%20)
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