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Tasya [4]
4 years ago
10

Isaiah is 10 years younger than his sister. The sum of their ages is no more than 34 years. Write an inequality that can be used

to represent this situation in the box, where x represents Isaiah’s sister's age.
Mathematics
2 answers:
Veseljchak [2.6K]4 years ago
6 0

Answer:

Isaiah's Sister age < = 22 (x <= 22)

Step-by-step explanation:

Topic: Inequalities

You have to be able to build two unkown system equations, so let's call

I = Isaiah's Age

x = Isaiah's Sister's Age

you know that Isaiah is 10 years younger than ger sister

so you have that

I  = x -10

and also you know that the sum of their ages don't exceed 34

I + x <= 34

with this information you can use substitution to find out the inequality for Isaiah's Sister's age as it follows

I + x <= 34 replacing I = x - 10 we have that

x - 10 + x <= 34 and then

2x - 10 <= 34 finding x then we have that

2x <= 34 + 10 so

2x <= 44 and we find that x <= 22

so by doing this we found that Isaiah's Sister cannot be older than 22, try doing the same for Isaiah!

son4ous [18]4 years ago
3 0

x - Isaiah’s sister's age.

(x - 10) -   Isaiah’s age.

The sum of their ages  is

x + (x-10)= 2x - 10

The sum of their ages is no more than 34 years:

2x - 10 ≤ 34.

Or we can simplify this inequality,

x - 5 ≤ 17.

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There were 42 students who took a test in mathematics.there were 36 students who passed test 1, and there were 38 who passed tes
Keith_Richards [23]
We are giiven with two realms:  36 students who passed test 1 and <span>38 who passed test 2 in which 42 students overall took the test. to determine U' or those who didn't pass either of the tests, then we use the formula:  
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Part of a regression output is provided below. Some of the information has been omitted.
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Answer:

301.189

Step-by-step explanation:

Given the table :

Source of Variation - - SS - - - df - - - MS - - - - F

Regression - - - - - -3177.17 - - -2 - - 1588.6

Residual - - - - - - - - ______ --17 - - -17.717

Total - - - - - - - - - - 3478.36 - - 19

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The Sum of Square RESIDUAL (SSR), Mean Square Residual (MSR) and Degree of Freedom RESIDUAL (DFR) are related by the formular :

MSR = SSR / DFR

Hence,

SSR = MSR × DFR

Fr the table ;

MSR = 17.717 ; DFR = 17

SSR = (17.717 × 17)

SSR = 301.189

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1/5 of chocolate is separated into 3

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