The last part answers the first part for you, just look at the y-values.
In other words:
<em>A'</em><em> </em>(-8, 2)
<em>B'</em> (-4, 3)
<em>C'</em> (-2, 8)
<em>D'</em> (-10, 6)
Explanation:
When you reflect any point over the x-axis, the y-value of the ordered pair is going to change.
This makes sense especially considering that the x-axis is horizontal, so the only way you could cross is to move up or down. If you were to move left or right, you'd only be able to cross the y-axis, since it's vertical.
Now for the last part, as I mentioned above, if you are reflecting across the y-axis, the x-values of the ordered pair is going to change.
<em>A'</em><em>'</em> (8, 2)
<em>B'</em><em>'</em> (4, 3)
<em>C'</em><em>'</em> (2, 8)
<em>D'</em><em>'</em> (10, 6)
Take note that the only thing that changes for the respective value is its sign, while the number itself stays the same.
Answer:
Step-by-step explanation:
there's no graph selection attached. Can you upload it and then I can help?
(2,3) so x=2, y=3 and h=(2^2+3^2)^(1/2)=√13
sina=3/√13, cosa=2/√13, tana=3/2
Afterwards multiply sina and cosa by √13/√13 and get sina=(3√13)/13 and cosa=(2√13)/13
O it is not correct he can find the correct sum by counting and adding 8,9,10 so the answer is ten he was one of his answer he must not of counted right
