The relationship between Sabir and calories he burns can be modeled using a linear function given by:
y=ax+b
where
a=slope
b=y-intercept
from the graph, the slope will be given as follows:
taking points (3,15) and (12,60)
a=(60-15)/(12-3)=5 calories/minute
thus using the slope and a point (3,15) the equation will be:
a(x1-x)=(y1-y)
plugging the values we obtain:
5(x-3)=y-15
5x-15=y-15
thus
y=5x
thus the equation is:
y=5x
Answer:
Quotient = 3
Step-by-step explanation:
We need to solve the given expression :
It can be done as follows :
As, 
So,
Hence, the required quotient is 3.
The straight lines mean absolute value
so x = -16 and x = 16
7-5 = 2
2+1 = 3
3x100 = 300
300 + 26 = 326
