Brita have 323 in her account before the withdrawal
Answer:
see below
Step-by-step explanation:
The equation for half life is
n = no e ^ (-kt)
Where no is the initial amount of a substance , k is the constant of decay and t is the time
no = 9.8
1/2 of that amount is 4.9 so n = 4.9 and t = 100 years
4.9 = 9.8 e^ (-k 100)
Divide each side by 9.8
1/2 = e ^ -100k
Take the natural log of each side
ln(1/2) = ln(e^(-100k))
ln(1/2) = -100k
Divide each side by -100
-ln(.5)/100 = k
Our equation in years is
n = 9.8 e ^ (ln.5)/100 t)
Approximating ln(.5)/100 =-.006931472
n = 9.8 e^(-.006931472 t) when t is in years
Now changing to days
100 years = 100*365 days/year
36500 days
Substituting this in for t
4.9 = 9.8 e^ (-k 36500)
Take the natural log of each side
ln(1/2) = ln(e^(-36500k))
ln(1/2) = -36500k
Divide each side by -100
-ln(.5)/36500 = k
Our equation in years is
n = 9.8 e ^ (ln.5)/36500 d)
Approximating ln(.5)/365=-.00001899
n = 9.8 e^(-.00001899 d) when d is in days
Can you translate into English please :)
Given:
The given quadratic equation is:
To find:
The solution for the given quadratic equation in simplest form by using the quadratic formula.
Solution:
Consider a quadratic equation is defined as 
, then the quadratic formula is:
The given quadratic equation is:
We have, 
. Using the quadratic formula, we get
![[\because \sqrt{-a}=i\sqrt{a}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Csqrt%7B-a%7D%3Di%5Csqrt%7Ba%7D%5D)
The solutions of the given equations are 
and 
.
Hence, the correct option is B.
Sela had 40 coins 4 months ago because 240 divided by six is 40.
