sela put 6 times as many coins now as she had 4 months ago. if sela has 240 coins now, how many did she have 4 months ago

Mathematics

2 answers:

scoray [572]3 years ago

6 0

She put 24 coins 4 months ago because 6 times 4 is 24.

yuradex [85]3 years ago

5 0

Sela had 40 coins 4 months ago because 240 divided by six is 40.

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(a) Use Euler's method with step size 0.2 to estimate y(1.4), where y(x) is the solution of the initial-value problem y' = 4x −

Verizon [17]

Answer:

$y\left(1.4\right)=0.992$ .

Step-by-step explanation:

The Euler's method states that $y_{n+1}=y_n+h \cdot f \left(x_n, y_n \right)$ , where $x_{n+1}=x_n + h$ .

To find $y\left(1.4 \right)$ for $y'=- 4 x y + 4 x$ when $y\left(1 \right)=0$ , with step size $h=0.2$ using the Euler's method you must:

We have that $h=0.2=\frac{1}{5}$ , $x_0=1$ , $y_0=0$ , $f(x,y)=- 4 x y + 4 x$ .

Step 1.

$x_{1}=x_{0}+h=1+\frac{1}{5}=\frac{6}{5}$

$y\left(x_{1}\right)=y\left( \frac{6}{5} \right)=y_{1}=y_{0}+h \cdot f \left(x_{0}, y_{0} \right)=0+h \cdot f \left(1, 0 \right)=0 + \frac{1}{5} \cdot \left(4.0 \right)=0.8$

Step 2.

$x_{2}=x_{1}+h=\frac{6}{5}+\frac{1}{5}=\frac{7}{5}=1.4$

$y\left(x_{2}\right)=y\left( \frac{7}{5} \right)=y_{2}=y_{1}+h \cdot f \left(x_{1}, y_{1} \right)=0.8+h \cdot f \left(\frac{6}{5}, 0.8 \right)=0.8 + \frac{1}{5} \cdot \left(0.96 \right)=0.992$