The perimeter of the shape is 43 centimeters. The area is 48 centimeters.
Answer:
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality
<u>Algebra I</u>
- Functions
- Function Notation
- Coordinates (x, y)
<u>Calculus</u>
Derivatives
Derivative Notation
Antiderivatives - Integrals
Integration Constant C
Integration Rule [Reverse Power Rule]:
Integration Property [Multiplied Constant]:
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
Point (0, 18)
<u>Step 2: Find General Solution</u>
<em>Use integration</em>
- [Derivative] Rewrite:
- [Equality Property] Integrate both sides:
- [Left Integral] Integrate [Integration Rule - Reverse Power Rule]:
- [Right Integral] Rewrite [Integration Property - Multiplied Constant]:
- [Right Integral] Integrate [Integration Rule - Reverse Power Rule]:
- Multiply:
<u>Step 3: Find Particular Solution</u>
- Substitute in point [Function]:
- Simplify:
- Add:
- Rewrite:
- Substitute in <em>C</em> [Function]:
Topic: AP Calculus AB/BC (Calculus I/II)
Unit: Integration
Book: College Calculus 10e
Answer:
the answer is G
which is 6.2*10 to the 9th power.
Step-by-step explanation:
In scientific notation you must leave one digit to the place value of ones
so that one digit is 6
So ue come up with 6.2 when ue eliminate all other zeros and end the decimal point between 6 and 2 and that way you have 6.2*10 to the 9th power
Answer:
The answer is below
Step-by-step explanation:
Speed is the time rate of change of velocity, it is the ratio of distance to time.
Mr. Fowles runs at a steady 4.2 miles per hour. The time taken to cover 26 miles is:
speed = distance / time
time = distance / speed = 26 / 4.2 = 6.19 hour
I run at 3 miles per hour. I was given 3 mile lead, so the remaining distance is 23 miles (26 - 3). The time needed to complete the 23 miles is:
time = distance / speed = 23 / 3 = 7.67 hour
a) Let d be the distance Mr Fowles catches me. Hence:
time = (d + 3)/4.2; also time = d/3
(d + 3)/4.2 = d/3
3d + 9 = 4.2d
1.2d = 9
d = 7.5 miles
He would catch me at 10.5 (7.5 + 3) miles from the starting point.
b) Mr. fowles finishes after 6.19 hour. At that time, the distance is have covered is:
distance = 6.19 * 3 mi/hr = 18.57 mile
Distance behind = 23 mile - 18.57 = 4.43 mile
c) time longer = 7.67 hour - 6.19 hour = 1.48 hour
All you have to do is divde hope this helps thank ylu