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Murljashka [212]
3 years ago
8

What processes above releases carbon dioxide into the atmosphere?

Biology
1 answer:
kaheart [24]3 years ago
6 0
During cellular respiration, glucose and oxygen<span> are changed into energy and carbon dioxide. Therefore, carbon dioxide is released into the atmosphere during the process of cellular respiration. Respiration is also the process by which once-living (organic) organisms are decomposed.</span>
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What effect do producers have on a food<br> chain?
Arada [10]

Answer:

Producers are the foundation of a food chain.

Explanation:

They provide energy for all of the consumers in an ecosystem.

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SCIENCE HELP 10 POINTS!!!!
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Which regions of the nephron function independently of hormonal control for the most part?
alexgriva [62]

Answer:

Renal corpuscle, proximal tubule, and loop of henle.

Explanation:

Renal corpuscle is blood filtering part of the nephron which consist of Bowman's capsule and glomerulus. It works independently of hormonal control and filter the blood circulate through this glomerulus.

Proximal tubule is the component of nephron which starts from the renal pole of Bowman's capsule to the loop of henle and it involves in the selective reabsorption of glucose, peptides, water and other nutrients from tubule to the blood. It works independently of hormonal control.

Loop of henle is the U shaped part of nephron which is responsible for absorption of water and sodium chloride from urine to back into blood circulation. It is also work independently of hormonal control.

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4 years ago
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What molecule can mix with water and i also a source of energy and a storage area?
elena-s [515]
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3 years ago
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Deer ticks can carry both Lyme disease and human granulocytic ehrlichiosis (HGE). In a study of ticks in the Midwest, it was fou
Nostrana [21]

Answer:

(a) 0.16

(b) 1

Explanation:

Let Probability that ticks in the Midwest carried Lyme disease, P(L) = 0.16

Probability that ticks in the Midwest carried HGE disease, P(H) = 0.10

Probability that ticks in the Midwest carried either Lyme disease or HGE disease, P(L \bigcup H) = 0.10

(a) Probability that a tick carries both Lyme disease (L) and HE (H) is given by

    P(L \bigcap H);

As we know that P(A \bigcup B) = P(A) + P(B) - P(A \bigcap B)

So, in our question;

       P(L \bigcup H) = P(L) + P(H) - P(L \bigcap H)

        0.10 = 0.16 + 0.10 - P(L \bigcap H)

       P(L \bigcap H) = 0.16 + 0.10 - 0.10 = 0.16

Therefore, the probability that a tick carries both Lyme disease (L) and HE (H) is 0.16 or 16% .

(b) <em>Conditional Probability P(A/B) is given by</em> = \frac{P(A\bigcap B)}{P(B)}

So, the conditional probability that a tick has HE given that it has Lyme disease is given by = P(H/L)

    P(H/L) = \frac{P(H\bigcap L)}{P(L)} = \frac{0.16}{0.16} = 1 .

3 0
3 years ago
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