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Degger [83]
4 years ago
6

The coordinates of quadrilateral FGHJ are F(-5, -3), G(-3, 3), H(3, 5), and J(7, -1).

Mathematics
1 answer:
scoundrel [369]4 years ago
5 0

To find the midpoint of line FG, we have to use the following midpoint formula , which is

(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2})

In the given question,

x1= -5, y1= -3 , x2=-3, y2=3

Substituting the values of x1,y1,x2 and y2 in the formula of the midpoint, we will get

(\frac{-5-3}{2},\frac{-3+3}{2})  =(-4,0)

So the midpoint of the given line is (-4,0) and hence the correct option is the first option .

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4 0
3 years ago
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Step-by-step explanation:

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4 0
3 years ago
Use the distributive property to factor the expression below.
Tems11 [23]

Answer:

D. 5(x^2+5)

Step-by-step explanation:

5x^2+25

Viewing the two terms 5 is divisible by both

5X^2/5 +25/5

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Therefore the equation will be represented by

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4 0
3 years ago
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Sati [7]
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5 0
3 years ago
7 cards are drawn from a standard deck of 52 playing cards. How many different 7-card hands are possible if the drawing is done
Vladimir [108]

Answer:

The number of different 7 card hands possibility is  133784560

Step-by-step explanation:

The computation of the number of different 7 card hands possibility is shown below:

Here we use the combination as the orders of choosing it is not significant

So,

The number of the different hands possible would be

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= 52! ÷ (7! × (52 - 7)!)

= 133784560

Hence, the number of different 7 card hands possibility is  133784560

4 0
3 years ago
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