Question

Factor this expression completely and then place the factors in the proper location on the grid. 36y2 - 1

Answer 1

I'm assuming that y2 means y^2 or y squared. In that case, your factors will be (6y+1) and (6y-1). 

Answer 2

Answer:

The factors of tex]36y^2-1[/tex] are $(6y+1)(6y-1)$

Step-by-step explanation:

Consider the given expression $36y^2-1$

We have to factorize it completely  and then place the factors on grid.

Consider the given expression  $36y^2-1$

We know algebraic identity, $a^2-b^2=(a-b)(a+b)$

Using above stated algebraic identity , we have,

$36y^2$ can be written as $6y \times 6y$

$36y^2-1=(6y)^2-1^2=(6y+1)(6y-1)$

Thus, the factors of tex]36y^2-1[/tex] are $(6y+1)(6y-1)$

Below attachment shows the placement on grid.