The value of x is 1.
The value of y is 4.
Solution:
Given TQRS is a rhombus.
<u>Property of rhombus:
</u>
Diagonals bisect each other.
In diagonal TR
⇒ 3x + 2 = y + 1
⇒ 3x – y = –1 – – – – (1)
In diagonal QS
⇒ x + 3 = y
⇒ x – y = –3 – – – – (2)
Solve (1) and (2) by subtracting
⇒ 3x – y – (x – y) = –1 – (–3)
⇒ 3x – y – x + y = –1 + 3
⇒ 2x = 2
⇒ x = 1
Substitute x = 1 in equation (2), we get
⇒ 1 – y = –3
⇒ –y = –3 – 1
⇒ –y = –4
⇒ y = 4
The value of x is 1.
The value of y is 4.
Answer:
Step-by-step explanation:
A = 1/4 pie d2
= 1/4(22/7)(12)2
= 1/4(22/7)144
= 113.1
Answer:
10 feet per second most prob
Step-by-step explanation:
Answer:
155 cm2
Step-by-step explanation:
3 x 4/2=6
6 x 2=12
5 x 11=55
55 x 2=110
3 x 11=33
12+110+33=155
I found the surface area of the triangular prism by calculating every side of the area and add it up.
Answer:
3.8 seconds
Step-by-step explanation:
Given equation
When the ball hits the ground then height is 0
So we replace h with 0 and solve for t
a= -16 , b= 60 and c= 5
Apply quadratic formula to solve for t
=![\frac{-60+\sqrt{60^2-4\left(-16\right)\cdot \:5}}{2\left(-16\right)}[/tex[tex]=\frac{-60+-\sqrt{3920}}{-32}](https://tex.z-dn.net/?f=%5Cfrac%7B-60%2B%5Csqrt%7B60%5E2-4%5Cleft%28-16%5Cright%29%5Ccdot%20%5C%3A5%7D%7D%7B2%5Cleft%28-16%5Cright%29%7D%5B%2Ftex%3C%2Fp%3E%3Cp%3E%5Btex%5D%3D%5Cfrac%7B-60%2B-%5Csqrt%7B3920%7D%7D%7B-32%7D)
Now make two fractions and solve for x
t= 
=-0.0815
t= 
=3.83
So answer is 3.8 seconds
