Ask question

Ask question

All categories

2 years ago

10

I mark brainliest for all my questions that are answered right :) thx for helping me

1 answer:

allsm [11]2 years ago

8 0

The correct answer is y= 0.513(1.833)^x

Explain

We will use the equation on this form

Y=ab^x

Let’s us plug in the coordinates of first point

(X, y) , ( 9, 120)

We will have

Y=ab^x

120= ab^9

Our equation for a will be

Ab^9 = 120

ab ^9 / b^9 = 120/ b^9

a = 120/ b^9

So will have

Y= 120/ b^9 • b^x

Then we will plug in coordinates for the second point

( x,y) = ( 10, 220)

We will have

Y= 120/b^9 • b^x

220 = 120/b^9 • b^10-9

220= 120b

Divide both side by 120

B= 11/6

B= 1.833333 = 1.833

Let’s plug in the value b=11/6 to our equation for a

A= 120/b^9

A= 120/ 11/6^9

A= 120/11^9/6^9

A=120 • 6^9 / 11^9

= 0.51285 which equal to 0.513

So therefore the answer is

Y= 0.513(1.833)^x

I hope this help you

:D

You might be interested in

2/(x^2)=4/x+1<br>can any one solve this for me please

levacccp [35]

2/X^2=4/X+1 times by both denominators
2(x+1)=4(x^2)
2x+2=4x^2
4x^2-2x-2=0
(2x+1)(2x-2)=0
x=2x+1 or 2x-2
x=-1/2 or 1

5 0

3 years ago

5 divided by 978 with remainder

grigory [225]

Hi!

978 can't go into 5 at all, so the answer is 0 R: 978

Hope this helps! :)

-Peredhel

6 0

3 years ago

Read 2 more answers

6. If you draw 35 lines on a piece of paper so that no two lines are parallel to each

umka2103 [35]

The point of intersection is the point where lines intersect.

<em>There will be 595 intersections for 35 lines, where no 3 lines are concurrent.</em>

<em />

Given

<em /> $n = 35$ <em> --- the number of lines</em>

<em /> $d = 3$ <em> --- no three lines are concurrent</em>

<em />

When no three line are concurrent, it means that no three lines meet at the same point.

<u>So, the sequence of intersection is:</u>

<em>0 intersection for 1 line</em>
<em>1 intersection for 2 lines</em>
<em>3 intersections for 3 lines</em>
<em>6 intersections for 4 lines</em>

<em />

Following the above sequence, the number of intersections for n lines is:

$n_k = \frac{n \times (n - 1)}{2}$

In this case, $n = 35.$

So, we have:

$n_k = \frac{35 \times (35 - 1)}{2}$

$n_k = \frac{35 \times 34}{2}$

$n_k = 35 \times 17$

$n_k = 595$

<em>Hence, there will be 595 intersections for 35 lines, where no 3 lines are concurrent.</em>

<em />

Read more about lines of intersections at:

brainly.com/question/22368617

7 0

2 years ago

Read 2 more answers

I'm not sure how to do the problem in the image I attached below... help.

yanalaym [24]

The answer is 5
Your welcome :)

3 0

2 years ago

Read 2 more answers

11 = -d + 15<br> PLEASE ANSWER FAST

Oksanka [162]

Answer:

<h2>d=4</h2>

Step-by-step explanation:

Let's solve your equation step-by-step.

11=−d+15

Step 1: Flip the equation.

−d+15=11

Step 2: Subtract 15 from both sides.

−d+15−15=11−15

−d=−4

Step 3: Divide both sides by -1.

−d/−1=−4/−1

4 0

2 years ago

Read 2 more answers