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Leni [432]
3 years ago
12

Change the decimal to a fraction and reduce .62

Mathematics
1 answer:
Len [333]3 years ago
6 0

Answer:

31/50

Step-by-step explanation:

0.62 = 62/100 = 31/50

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Which of the following points lie in the solution set to the following system of inequalities?
emmasim [6.3K]
<h3>Answer:</h3>

B. (5, -2)

<h3>Step-by-step explanation:</h3>

Try the points in the inequalities and see what works. Here, we evaluate the point in the first inequality, and if that works, then the second inequality.

A. 2 ≤ -(-5) -5 . . . ⇒ . . . 2 ≤ 0 . . . false

B. -2 ≤ 5 -5 . . . true

... -2 ≥ -(5) -4 . . . true . . . . . . selection B is a viable choice

C. we know from A that the first inequality will be satisfied

... -2 ≥ -(-5) -4 . . . ⇒ . . . -2 ≥ 1 . . . false

D. 2 ≤ 5 -5 . . . . false

6 0
3 years ago
Helppppp thanksssssssss
klemol [59]
The 3rd or 1st one I'm not sure which one but u have an idea of what it might be
4 0
3 years ago
Which equation can be used to solve for m, the greater integer? m(m – 3) = 108 m(m + 3) = 108 (m + 3)(m – 3) = 108 (m – 12)(m –
nata0808 [166]

Answer:

m(m-3)=108

Step-by-step explanation:

Complete question below:

Two positive integers are 3 units apart on a number line. Their product is 108.

Which equation can be used to solve for m, the greater integer?

m(m – 3) = 108

m(m + 3) = 108

(m + 3)(m – 3) = 108

(m – 12)(m – 9) = 108

Solution

On the number line,

Let

m= larger integer

The integers are 3 numbers apart on the number line, so

m-3=smaller integer

The product (×) of the larger and smaller integers=108

(m)*(m-3)=108

m(m-3)=108

Therefore, the equation that can be used to solve for m, the larger integer is:

 m(m – 3) = 108 

5 0
3 years ago
Plz help me .. I am really stumped!!!!!!! part of the set for a play is a big triangular piece of plywood. the area of the trian
saul85 [17]
The way to find the area of a triangle is A=\frac{B*H}{2}
if the base is 3 feet longer then the height we can write it like this B=H+3

now we can add it to our area equation
20=\frac{H(H+3)}{2}
20=\frac{ h^{2} +3h}{2}
40=H^{2}+3H
10\frac{1}{3}=H^{2}
h=3.2ft

3 0
3 years ago
Identify the steps to completing the square. Its on my algebra 2 homework and i have no idea what it means
Mrrafil [7]
1. your leading coefficient has to be 1 (nothing before the x^2). If there is you have to divide that out before you start.
2. Move your constant (the number without any x attached) to the other side of the equation
3. take 1/2 of the b term (the one with the x attached) and then square it and then add it to both sides
4. Factor the left side
5. Set each factor equal to 0 and solve

Here is an example:

4x^2-24x+20=0
The first term is not a 1 so we have to divide it out by 4 first
x^2-6x+5=0
Move the 5 to the other side.  It becomes negative.
x^2-6x=-5
Take 1/2 of 6 (3) then square it (9) and add it to both sides.
x^2-6x+9=-5+9
Factor the left side
(x-3)(x-3)=4
(x-3)^2=4
To solve you need to square root both sides
x-3=+/-
x-3=+/-2
x=3+2=5
x=3-2=1
Those would be your two answers.

<span>Hope that helps</span>
4 0
3 years ago
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