Answer:
4. A post-lunch nap decreases the amount of time it takes males to sprint 20 meters.
Step-by-step explanation:
This question wants us to state the claim and the hypothesis.
This researchers claim can be found in the first sentence of this question.
Claim: post lunch nap decreases the time it takes to run for 20 meters.
The correct answer option for the claim is the 4th answer option. And it means that sleeping after lunch reduces the time it takes males to run in a 20m race.
B. Hypothesis
H0: Ud <= 0
H1: Ud > 0
d = is the race time without a nap - race time with a nap
Answer:
The integrals was calculated.
Step-by-step explanation:
We calculate integrals, and we get:
1) ∫ x^4 ln(x) dx=\frac{x^5 · ln(x)}{5} - \frac{x^5}{25}
2) ∫ arcsin(y) dy= y arcsin(y)+\sqrt{1-y²}
3) ∫ e^{-θ} cos(3θ) dθ = \frac{e^{-θ} ( 3sin(3θ)-cos(3θ) )}{10}
4) \int\limits^1_0 {x^3 · \sqrt{4+x^2} } \, dx = \frac{x²(x²+4)^{3/2}}{5} - \frac{8(x²+4)^{3/2}}{15} = \frac{64}{15} - \frac{5^{3/2}}{3}
5) \int\limits^{π/8}_0 {cos^4 (2x) } \, dx =\frac{sin(8x} + 8sin(4x)+24x}{6}=
=\frac{3π+8}{64}
6) ∫ sin^3 (x) dx = \frac{cos^3 (x)}{3} - cos x
7) ∫ sec^4 (x) tan^3 (x) dx = \frac{tan^6(x)}{6} + \frac{tan^4(x)}{4}
8) ∫ tan^5 (x) sec(x) dx = \frac{sec^5 (x)}{5} -\frac{2sec^3 (x)}{3}+ sec x
6,400 parts are needed to make 1 ton of scrap metal
Answer:
Here it is!
Step-by-step explanation:
A , b & c ?
lmk if i’m wrong tho
