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xenn [34]
3 years ago
8

Can you simplify these please thank you

Mathematics
1 answer:
kap26 [50]3 years ago
7 0
-4(9-3)/(8-2) = -4

(8^2-2^5)/(24/6)+3^2= 17

5(16-5)-1/(4^2-7) = 6

Hope this helps! Please rate if I helped you! Any questions please just ask! Thanks!!
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In ΔXYZ, ∠X=59° and ∠Y=21°. ∠XWZ=90° and XY=6.1. Find the length of XW to the nearest 10th.
dlinn [17]

Answer:

this is question is wrong it you typed it wrong

how come the triangle named XYZ and the angle wxz and if there 2 triangles one must be a failure because there is no triangle which all his angels equals more than 180°

look again and if possible take a picture of the question

3 0
3 years ago
What is the value of the expression?<br> 5(6-10)
MArishka [77]

Answer:

-20

Step-by-step explanation:

multiply 5 and 6 then 5 and -10

30-50=-20

6 0
3 years ago
Expand this question. <br><br> 3(x+2)
irakobra [83]

Answer:

3(x+2)

3x+6

Step-by-step explanation:

We should multiply it by 3

3 0
2 years ago
Read 2 more answers
A trimming operation at a local manufacturer produces rods whose length conforms to unifrom distribution with a minimum of 18cm
MariettaO [177]

Answer:

The probability that randomly selected road will be at least 25.8 cm long will be 48%.

Step-by-step explanation:

Given: uniform distribution with min and max values of 18 and 33 respectively.

To find : probability density for upper cumulative frequency i.e 25.8 at least means x\geq25.8  upto 33 cm i.e the maximum limit of function.

Solution:

we have by definition , of uniform distribution

we get , probability density function defines as :

<em>F(x,a,b)= </em>\frac{1}{b-a}<em>   </em>a\leq x\leq b

            =1/(33-18)=1/15=0.0667.

this is probability density function.

here the x=25.8 , a=18 and b=33

for lower cumulative frequency it defines as ;

P(x,a,b)=\frac{x-a}{b-a} =25.8-18/33-18=0.52

for upper cumulative frequency it defines as ;

Q(x,a,b)=b-x/b-a=33-25.8/33-18=0.48

here at least 25.8 cm probability means it should be greater than a value(18cm) hence it is provided by the upper cumulative frequency

i.e. Q(x,a,b)=0.48

The probability that randomly selected road will be at least 25.8 cm long will be 48%.

7 0
2 years ago
Samuel surveys 15 students at his school and asks them: "How many candies per day do you usually eat?"
shepuryov [24]

Answer:

Minimum number of candies:

0

Maximum number of candies:

13

Range:

13

Median number of candies:

4

Interquartile range:

5

Step-by-step explanation: There u go

6 0
3 years ago
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