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zhuklara [117]
2 years ago
15

50 points will mark brainiest match each exponential function to it's rate of change

Mathematics
1 answer:
nordsb [41]2 years ago
8 0

Step-by-step explanation:

An exponential function of a^x (a>0) is always ln(a)*a^x, as a^x can be rewritten in e^(ln(a)*x). ... The derivative shows, that the rate of change is similiar to the function itself. For 0<a<1, ln(a) becomes negative and so is the rate of change.

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The three perpendicular bisectors of a triangle intersect at the_____.
lubasha [3.4K]

Answer:

centroid

Step-by-step explanation:

Definition of a centroid

4 0
3 years ago
What are the answers since I’m confused an all over the place
dalvyx [7]
3 squares = 4 circles, so (number of squares)/(number of circles) = 3/4.
3/4 = 12/16
:::::
4 squares = 2 circles, so (number of squares)/(number of circles) = 4/2.
4/2 = 2/1
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2 squares = 5 circles, so (number of squares)/(number of circles) = 2/5.
2/5 = 4/10

7 0
2 years ago
Segments
Kazeer [188]

Given

AB  and  CD  intersect

AC,  CB,  BD  and  AD  are congruent.

Prove that AB  is the bisector of ∠CAD and ray  CD  is the bisector of ∠ACB.

and AB  and  CD  are perpendicular.

To proof

Bisector

<em>A bisector is that which cut an angle in two equal parts.</em>

In ΔACB and ΔADB

AD = AC  ( Given )

AB = AB   ( common )

BC = DB  ( Given )

by SSS congurence property

we have

ΔACB ≅ΔADB

∠CAB =∠ DAB

∠CBA = ∠DBA

( By corresponding sides of the congurent triangle )

Thus AB is the bisector of the ∠CAD.

InΔ DAC and ΔDBC

AD = DB (Given)

AC = CB  ( Given )

CD = CD (common)

By SSS congurence property

ΔDAC≅ Δ DBC

∠  ACD =∠ BCD

∠ADC =∠BDC

( By corresponding sides of the congurent triangle )

Therefore CD is the bisector of the CAD.

In ΔBOC andΔ BOD

BO = BO ( Common )

∠BCO = ∠BDO

( As prove above ΔACB ≅ΔADB

Thus ∠ACB = ∠ADB by corresponding sides of the congurent triangle , CD is a bisector

∠BCO = ∠BDO )

 CB = DB ( given )

by SAS congurence property

ΔBOC ≅ ΔBOD

∠BOC =∠ BOD

∠BOC +∠ BOD = 180 °( Linear pair )

2∠ BOC = 180°

∠BOC = 90°

∠BOC =∠ BOD = 90°

also

In ΔCOA and ΔAOD

AO = AO ( Common )

∠ACO =∠ ADO

(  As prove above ΔACB ≅ΔADB Thus ACB = ADB by corresponding sides of congurent triangle ,CD is a bisector

thus  ∠ACO = ∠ADO )

AC =AD ( given )

by SAS congurence property

Δ COA ≅ ΔAOD

∠AOC = ∠AOD

( By corresponding angle of corresponding sides )

∠AOC + ∠AOD = 180°

2∠ AOC = 180°   ( Linear pair )

∠AOC = 90°

∠AOC = ∠AOD = 90 °

Thus AB  and  CD  are perpendicular.

Hence proved









   


 



6 0
3 years ago
Express the number 0.0000005864 in scientific notation
telo118 [61]

Answer:

5.874^7

Step-by-step explanation:

i just need more characters here

5 0
3 years ago
a 10 ft ladder leans against a wall with its foot braced 3ft. from wall's base how far up the wall does the ladder resach
geniusboy [140]
Ladder makes a right triangle with the wall and ground. The hypotenuse = length of the ladder = 10 ft 
Let the height be h
By Pythagorean theorem 
10^2 = 3^2 + h^2 
h^2 = 10^2 - 3^2 = 100 - 9 = 91
h = sqrt( 91) = 9.54 ft
6 0
3 years ago
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