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liraira [26]
3 years ago
14

At midnight, the temperatures is -4 degrees Celsius. At noon, the temperature is 20 degrees Celsius. By how many more degrees Ce

lsius did the temperature rise?
Mathematics
1 answer:
8_murik_8 [283]3 years ago
4 0
24 degrees celcius
-4 + 4 = 0
0 + 20 = 20
20 + 4 = 24 degrees celcius
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Four times the sum of three consecutive odd integers is seven hundred sixty-five less than three times the product of the larger
Andre45 [30]

Answer:

The consecutive odd integers are (15, 17, 19) or (-17, -15, -13).

Step-by-step explanation:

Let the three consecutive odd integers be: x-2,x\ and \ x+2

The condition given is:

4[x-2+x+x+2]=3x(x+2)-765

Solve this for <em>x</em> as follows:

4[x-2+x+x+2]=3x(x+2)-765\\4\times 3x=3x^{2}+6x-765\\3x^{2}-6x-765=0\\x^{2}-2x-255=0\\x^{2}-17x+15x-255=0\\x(x-17)+15(x-17)=0\\(x-17)(x+15)=0

  • If (x-17)=0 then the value of <em>x</em> is 17.

       The odd numbers are:

          x-2=17-2=15\\x=17\\x+2=17+2=19

  • If (x+15)=0 then the value of <em>x</em> is -15.

       The odd numbers are:

         x-2=-15-2=-17\\x=-15\\x+2=-15+2=-13

Thus, the consecutive odd integers are (15, 17, 19) or (-17, -15, -13).

7 0
3 years ago
Mixed nuts sell for $7.89 a pound. Leticia fills a bag and weighs it. The bag weighs 2.3 pounds. About how much will the bag of
Zigmanuir [339]

Answer:

About $16

Step-by-step explanation:

To find the answer first round the weight from, 2.3 to 2. Next round the price per pound from $7.89 to 8.00. Last, multiply the weight of the bag by the price per pound. I hope this was helpful. Have a wonderful day!

7 0
3 years ago
Read 2 more answers
indicate the equation of the line that is the perpendicular bisector of the segment with endpoints (4,1) and (2,-5)
bulgar [2K]

hmmm what would it be the bisector point of a line with those points?  let's check

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{4}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{-5}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left(\cfrac{2+4}{2}~,~\cfrac{-5+1}{2} \right)\implies \implies \left( \cfrac{6}{2}~,~\cfrac{-4}{2} \right)\implies (3,-2)

now, let's check the slope of those two points, bearing in mind that a perpendicular line will have a <u>negative reciprocal slope</u> to that one.

\bf (\stackrel{x_1}{4}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{-5}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-5-1}{2-4}\implies \cfrac{-6}{-2}\implies 3 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{3\implies \cfrac{3}{1}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{1}{3}}\qquad \stackrel{negative~reciprocal}{-\cfrac{1}{3}}}

so, we're really looking for the equation of a line whose slope is -1/3 and runs through (3, -2)

\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{-2})~\hspace{10em} slope = m\implies -\cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-2)=-\cfrac{1}{3}(x-3)\implies y+2=-\cfrac{1}{3}x+1 \\\\\\ y=-\cfrac{1}{3}x+1-2\implies y=-\cfrac{1}{3}x-1

7 0
3 years ago
Plz help !!!!!!!!!!!
prohojiy [21]

\sqrt[4]{x^3} = (x^3)^{\frac 1 4} = x^{\frac 3 4}

3 0
3 years ago
For a small party of 12 people the caterer offered a choice of a steak dinner for $12.00 per meal or a chicken dinner for $10.50
Natasha_Volkova [10]
Assuming one meal has been ordered for each person, let x and y represent the number of steaks and the number of chickens ordered, respectively. Then, we get the following system of linear equations.      x + y = 12               (Eq. 1)      12x + 10.5y = 138   (Eq. 2) If we plug y = 12 - x, which is from Eq. 1, into Eq. 2,      12x + 10.5(12 - x) = 138      1.5x + 126 = 138      1.5x = 12      x = 8 and plug x = 8 into Eq. 1, we get y = 4. So, they ordered 8 steaks and 4 chickens.
7 0
3 years ago
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