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3 years ago

How do i find the slope of 3x-2y= 3

Mathematics

1 answer:

Reika [66]3 years ago

6 0

Answer:

slope=3/2

Step-by-step explanation:

3x-2y=3

2y=3x-3

$y=\frac{3}{2} x-\frac{3}{2} \\compare ~with~y=mx+c\\slope~m=\frac{3}{2}$

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Answer number 2 for me plz and thank you

anyanavicka [17]

The answer to the question is 2:3

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2 years ago

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The following table shows the length and width of two rectangles:

zhannawk [14.2K]

Answer:

10x - 8 or 2( 5x - 4)

Step-by-step explanation:

Perimeter of a rectangle = 2( Length + Width)

<u>Rectangle A </u>

Length = x + 8,

Width = x - 1

$Perimeter_A = 2((x + 8) + ( x - 1))\\\\$

$= 2(x + 8 + x - 1) \\\\= 2(2x + 7)\\\\=4x + 14$

<u>Rectangle B</u>

Length = 4x + 5

Width = 3x - 2

$Perimeter _B= 2((4x + 5) + (3x-2))\\\\$

$=2(4x + 5 + 3x - 2)\\\\=2(7x + 3)\\\\=14x + 6$

$Perimeter_B - Perimeter_A = (14x +6)-(4x + 14) \\\\$

$=14x + 6 - 4x - 14\\\\=10x -8\\\\or \\\\=2(5x - 4)$

4 0

2 years ago

Bella is making button barrettes. She allows each of her friends to reach into her bag of buttons and randomly select a color. T

bija089 [108]

Pink 30/240

green 70/240

orange 100/240

blue 50/240

6 0

3 years ago

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PLEASE HELP WILL GIVE BRAINLIEST. Which of the following statments is true about the equation shown? Mark all that are true. t (

Vesna [10]

Answer:

a and c

Step-by-step explanation:

The equation of a quadratic in vertex form is

f(x) = a (x - h)² + k

where (h, k ) are the coordinates of the vertex and a is a multiplier

f(x) = (x - 5)² + 7 ← is in vertex form

Thus the function is quadratic → a

• If a > 0 then the grapg will open upwards

• If a < 0 then the graph will open downwards

Here a = 1 > 0 then graph will open upwards → c

8 0

2 years ago

Use the distance formula distance, to find the distance to the nearest tenth , between each pair of points A(6,2) and D(-3,-2)

marusya05 [52]

Answer:

The distance between A and D to the nearest tenth is;

$9.8\text{ units}$

Explanation:

Given the two points;

$A(6,2)\text{ and D(-3,-2)}$

Applying the distance between two points formula;

$d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}$

substituting the given coordinates we have;

$\begin{gathered} AD=\sqrt[]{(-3-6)^2+(-2-2)^2} \\ AD=\sqrt[]{(-9)^2+(-4)^2} \\ AD=\sqrt[]{81+16} \\ AD=\sqrt[]{97} \end{gathered}$

Simplifying;

$\begin{gathered} AD=9.8488578 \\ AD\approx9.8 \end{gathered}$

Therefore, the distance between A and D to the nearest tenth is;

$9.8\text{ units}$

4 0

1 year ago