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Hunter-Best [27]
4 years ago
11

If f(x) = 5x, what is f–1(x)?

Mathematics
2 answers:
Sergio039 [100]4 years ago
8 0
It would be 1/5x so C
rosijanka [135]4 years ago
5 0

Answer:

Correct option is:

f^{-1}(x)=\dfrac{x}{5}

Step-by-step explanation:

Let f(x)=y

Then, f^{-1}(y)=x

Hence, Value of x in terms of y gives the value of f^{-1}(x)

f(x)=y

i.e. 5x=y

i.e. x=y/5

Hence, f^{-1}(y)=\dfrac{y}{5}

Replacing y by x, we get

f^{-1}(x)=\dfrac{x}{5}

Hence, correct option is:

f^{-1}(x)=\dfrac{x}{5}

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Helppppppppppppp i need this homework done by today
lbvjy [14]

Answer: 13. -68

14. 36

15. -36

16. -3

17. 10

18. -4

19. 1310 ft

20. 330 ft

Step-by-step explanation:

13. 34*(-2)=-68

14. -9*(-4)=

-(9*(-4))=

-(-36)=36

15. 12*(-3)=-36

16. -12/4=-3

17. -20/(-2)=

20/2=10

18. 200/(-50)=-4

19. -1640*(-1)-(-330*(-1))=

1640-(-330*(-1))=

1640-330=1310 ft

20. -990*(-1)-(-660*(-1))=

990-(-660*(-1))=

990-660=330 ft

7 0
1 year ago
which values when substituted for x in the expression √x, will result in an irrational number? Select all that apply.
svetlana [45]
Answer:
x = 21
x = 2
x = pi
6 0
1 year ago
Write the standard form of the equation of the circle with the given characteristics. Center: (3, 5); Solution point: (−2, 17)
Angelina_Jolie [31]

\text{we know that the general equation of the circle is }\\
\\
(x-h)^2+(y-k)^2=r^2\\
\\
\text{where, (h,k) is the center of the circle and r is the radius.}\\
\\
\text{Given that the centered of the circle is at  }(h,k)=(3,5)\\
\text{and a solution point on circle is (-2,17).}\\
\\
\text{so the radius of the circle will be the distance between center and the }

\text{solution point. so using the distance formula, we have}\\
\\
\text{Radius, }r=\sqrt{(-2-3)^2+(17-5)^2}\\
\\
\Rightarrow r=\sqrt{25+144}\\
\\
\Rightarrow r=\sqrt{169}\\
\\
\Rightarrow r=13\\
\\
\text{Hence using the standard for of circle, equation of circle with center}\\
(h,k)=(3,5) \text{ and radius r=13 is}\\
\\
(x-3)^2+(y-5)^2=(13)^2\\
\\
\Rightarrow (x-3)^2+(y-5)^2=169

3 0
3 years ago
which expression represents purely real numbers and which expression represents non-real complex number?​
Lyrx [107]

Answer:

Step-by-step explanation:

Complex numbers are the numbers represented by the expression = a + bi

Here a = real part of the number

bi = imaginary part

a and b are the real numbers.

i^9=(i^2)^4.(i)

    =(-1)^{4}.i [Since, i^2=-1]

    =i

Therefore, its a non real complex number.

2 - \sqrt{-49} = 2-\sqrt{(-1)(7)^2}

               = 2-7\sqrt{-1}

               = 2-7i

This number is a Non real complex number.

\sqrt{(-18)^2}=18\sqrt{-1}

              = 18i

It's a non real complex number.

3 + 2i

It's a non real complex number.

-289

It's a purely real number.

4-32i^2=4-32(-1)

             = 4 + 32

             = 36

It's a purely real number.

6 0
3 years ago
Simplify: 6y + 5z + 8y – 3z
REY [17]
6y + 5z +8y- 3z \\
14y + 2z\\ \\
2 (7 y + z) 

7 0
3 years ago
Read 2 more answers
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